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3 years ago

A) Write 600 as the product of prime factors. Give your answer in index form.

Mathematics

2 answers:

dlinn [17]3 years ago

4 0

Answer:

3 × 5 × 5 × 2 × 2 × 2

Step-by-step explanation:

Make a factor tree.

But let me explain the above to prove it's correct.

3 × 5 = 15

15 × 5 = 75

75 × 2 = 150

150 × 2 = 300

300 × 2 = 600

Therefore 600 as a product of prime factors is: 3 × 5 × 5 × 2 × 2 × 2

andreev551 [17]3 years ago

4 0

Answer:

600= 3x5^2x2^3

HCF= 150

Step-by-step explanation:

srry for late response

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2 years ago

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3 years ago

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stira [4]

Answer:

$x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}$

a) $x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027$

b) $x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294$

Step-by-step explanation:

For this case we have the following function:

$P= 8000 (1- \frac{5}{5 +e^{-0.002 x}})$

We can solve for x like this. First we can reorder the expression like this:

$\frac{P}{8000} = 1- \frac{5}{5+e^{-0.002x}}$

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$\frac{40000}{8000-P} = 5 + e^{-0.002x}$

Now we can apply natura log on both sids and we got:

$ln[\frac{40000}{8000-P} -5] = ln e^{-0.002x}$

$ln [\frac{5P}{8000-P}] = -0.002x$

And if we solve for x we got:

$x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}$

Part a

For this case we can replace P = 200 and see what we got for x like this:

$x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027$

Part b

For this case we can replace P = 800 and see what we got for x like this:

$x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294$

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3 years ago