Given :
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by 
.
To Find :
Find the time at which the concentration is a maximum. b. Find the maximum concentration.
Solution :
For maximum value of x, K'(x) = 0.
Since, time cannot be negative, so ignoring x = -3 .
Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6
Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.
Hence, this is the required solution.
Answer:
x = 2
Step-by-step explanation:
AB/BC = AD/DE
= 
cross-multiply:
2+x = 4
x = 2
Answer:
D, (1,2)
Step-by-step explanation:
It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).
1. Plug in your x value (1 in this circumstance) and solve:
3(1) + 4y < 12
3 + 4y < 12
2. Plug in your y value (2 in this circumstance) and solve:
3 + 4(2) < 12
3 + 8 < 12
3. Solve
3 + 8 = 11
11 < 12
This isnt something I can do... But draw and label a tape diagram that goes from 0 to 30.
Answer:
Graph 4
Step-by-step explanation:
Parallel lines have no solution to the system of equation. Graph 4 is a set of parallel lines, so they will never intersect.
