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3 years ago

This stainless-steel fitting

1 answer:

7 0

Subtract the volume of the inside diameter from the volume of the outside diameter and then multiply that by the density.

Volume of outside:

PI x 1.8^2 x 3.9 = 39.67704 cubic cm

Volume of inside:

PI x 1.35^2 x 3.9 = 22.318335 cubic cm

Difference: 39.67704 - 22.318335 = 17.358705 cubic cm.

Mass = 17.358705 x 8 = 138.86964 grams. Round the answer as needed.

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WILL MARK BRAINLIEST! If a man walks 15 miles in 3 hours. How many miles can he walk in 7 hours?

Otrada [13]

Answer: He can walk 35 miles in 7 hours because 15x2=30 and 15/3 is 5.

3 0

4 years ago

Read 2 more answers

A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed i

Hunter-Best [27]

Answer:

a) σ/√n= 1.43 min

c) Margin of error 2.8028min

d) [30.1972; 35.8028]min

e) n=62 customers

Step-by-step explanation:

Hello!

The variable of interest is

X: Time a customer stays at a restaurant. (min)

A sample of 49 lunch customers was taken at a restaurant obtaining

X[bar]= 33 mi

The population standard deviation is known to be δ= 10min

a) and b)

There is no information about the distribution of the population, but we know that if the sample is large enough, n≥30, we can apply the central limit theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

Where μ is the population mean and σ²/n is the population variance of the sampling distribution.

The standard deviation of the mean is the square root of its variance:

√(σ²/n)= σ/√n= 10/√49= 10/7= 1.428≅ 1.43min

The CI for the population mean has the general structure "Point estimator" ± "Margin of error"

Considering that we approximated the sampling distribution to normal and the standard deviation is known, the statistic to use to estimate the population mean is Z= (X[bar]-μ)/(σ/√n)≈N(0;1)

The formula for the interval is:

[X[bar]± $Z_{1-\alpha /2}$ *(σ/√n)]

The margin of error of the 95% interval is:

$Z_{1-\alpha /2}= Z_{1-0.025}= Z_{0.975}= 1.96$

d= $Z_{1-\alpha /2}$ *(σ/√n)= 1.96* 1.43= 2.8028

[X[bar]± $Z_{1-\alpha /2}$ *(σ/√n)]

[33±2.8028]

[30.1972; 35.8028]min

Using a confidence level of 95% you'd expect that the interval [30.1972; 35.8028]min contains the true average of time the customers spend at the restaurant.

Considering the margin of error d=2.5min and the confidence level 95% you have to calculate the corresponding sample size to estimate the population mean. To do so you have to clear the value of n from the expression:

d= $Z_{1-\alpha /2}$ *(σ/√n)

$\frac{d}{Z_{1-\alpha /2}}$ = σ/√n

√n*( $\frac{d}{Z_{1-\alpha /2}}$ )= σ

√n= σ* ( $\frac{Z_{1-\alpha /2}}{d}$ )

n=( σ* ( $\frac{Z_{1-\alpha /2}}{d}$ ))²

n= (10* $\frac{1.96}{2.5}$ )²= 61.47≅ 62 customers

I hope this helps!

3 0

3 years ago

The volume of a prism is found by multiplying the area of the base by the height. A rectangular prism has a volume of 144 cm3 ,

docker41 [41]

The volume (V) of prism is the product of the area (A) of the base and its height (h). The area of the square base is the square of its width, 3 cm.
144 cm³ = (3 cm)² x h
The value of h from the equation is 16. Therefore, the height of the prism is 16 cm.

7 0

3 years ago

The histogram shows the prices of dinners at a local fine-dining restaurant.

Brut [27]

Answer:c

Step-by-step explanation:

3 0

3 years ago

A youth organization collected nickels and dimes for a charity drive. By the end of the 1-day drive, the youth had collected $63

uysha [10]

Let, the numbers of nickels be x.

Given, there were 5 times as many dimes as nickels.