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LUCKY_DIMON [66]
3 years ago
7

What are these numbers from least to greatest: 2.8, 2.75, 3.125, 2.2repeating

Mathematics
2 answers:
Anton [14]3 years ago
8 0
2.2(repeating), 2.75, 2.8, 3.125
Lynna [10]3 years ago
4 0
From least to greatest its 2.2 2.75 2.8 3.124
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mihalych1998 [28]

Answer:

im not sure but i think i hvae the answer in my phone but it has to chrge

Step-by-step explanation:

5 0
3 years ago
Find the slope of the line through the points (13,14) and (0,−1)
timofeeve [1]

Answer:

1.15 or \frac{15}{13}

Step-by-step explanation:

1. The slope can be found with this formula: \frac{y2-y1}{x2-x1}

2. Let's plug in the numbers: \frac{14--1}{13-0}

4. \frac{15}{13} ≈ 1.1538

6 0
2 years ago
Any help? I dont really understand what to do
il63 [147K]
Times the corner and bases

7 0
3 years ago
Read 2 more answers
write the equation of the perpendicular bisector that goes through the line segment with end points of A -1,-2 and B -2,-8
Dennis_Churaev [7]

Answer:

  2x +12y = -63 . . . in standard form

  y = -1/6x -21/4 . . . in slope-intercept form

Step-by-step explanation:

It is useful to find the midpoint of the segment. That is the average of the end points:

  M = ((-1, -2) +(-2, -8))/2 = ((-1-2)/2, (-2-8)/2) = (-3/2, -5)

It is also useful to find the changes in coordinates from B to A:

  Δ = A-B = (-1-(-2), -2-(-8)) = (1, 6)

From here, there are a couple of ways you can write the equation of the perpendicular line.

__

One way is to use the Δ values to compute the slope of the segment. The perpendicular line will have a slope that is the negative reciprocal of that.

  Δy/Δx = 6/1 = 6

  m = -1/6 . . . . . slope of the perpendicular line

Now we have a point and a slope for the desired line, so we can use a point-slope form of the equation for a line:

  y = m(x -h) +k

  y = (-1/6)(x -(-3/2)) +(-5)

  y = (-1/6)x -21/4 . . . . . . . . eliminate parentheses; point-slope form

__

Another way to write the perpendicular line is to use the Δ values directly as coefficients in the standard form equation:

  Δx(x -h) +Δy(y -k) = 0

  1(x -(-3/2)) + 6(y -(-5)) = 0 . . . substitute values

  x +6y +31.5 = 0 . . . . . . . . . . .collect terms

  2x +12y = -63 . . . . . . . . . . . . multiply by 2, put in standard form

7 0
3 years ago
Give the equation of the line which is perpendicular to y = 5x + 6 and goes through the point (- 15, 2)​
Reptile [31]

Answer:

x+5y+5=0

Step-by-step explanation:

y=5x+6

Therefore the gradient of the line = 5

Now reciprocate the gradient and negate it

i.e -1/5

let (x,y) and (-15,2) be points on the line

y-2/x-(-15)=-⅕

5y-10=-x-15

5y-10+15+x=0

x+5y+5=0

Therefore the equation of the line =

x+5y+5=0

7 0
3 years ago
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