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Elden [556K]
3 years ago
13

Please solve this problem (surface area). With work bc my teacher said I need to show work with my answer

Mathematics
1 answer:
gregori [183]3 years ago
5 0
There are two triangular faces and three rectangular faces.
The triangular faces are congruent, so they have the same area. We calculate one and we'll know both.
The three rectangles are different.

Triangular face (each)
Although you can hardly see in the colored figure, there is a small symbol on the right side showing that the 4 km side and the 3 km side of the triangles are perpendicular. That means those sides are the base and the height.
A = (1/2)bh = (1/2)(3 km)(4 km) = 6 km^2

Rectangular faces:
A = LW = 7 km * 3 km = 21 km^2
A = LW = 7 km * 5 km = 35 km^2
A = LW = 7 km * 4 km = 28 km^2

total surface area = 2 * 6 km^2 + 21 km^2 + 35 km^2 + 28 km^2

total surface area = 96 km^2
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A recent poll found that 35% of those surveyed are worried about aggressive drivers on the road. If three people are selected at
Ugo [173]

The probability that all three people surveyed is an independent probability and the calculated probability is 0.1225

The probability a surveyed driver is worried = 35%

  • P(worried) = 0.35

  • Number of people surveyed = 3

Since the probability of being worried is independent ;

  • Probability = P(A) × P(B) × P(C)

The probability that all 3 surveyed are worried :

  • P(worried) × P(worried) × P(worried)
  • (0.35 × 0.35 × 0.35) = 0.1225

Therefore, the probability that all three people surveyed are worried is : 0.1225

Learn more : brainly.com/question/18153040

5 0
2 years ago
Prompt Use the applet to select 20 different random samples of 100 part-time college students. For each sample the applet calcul
Ket [755]

Answer:

Yes, we can expect the given result

Step-by-step explanation:

The population proportion P = 0.60

the 95% confidence interval is ( 0.56, 0.76)

The 95% confidence that the true population proportion lies between the interval ( 0.56, 0.76)

Only 5% of 20 random samples i.e only 1 sample is not contain in the population proportion.

6 0
3 years ago
What is the first step in simplifying
seraphim [82]
Distribute the negative b and negative one to he terms in the parentheses
In an expression, if there area brackets, you always have to expand THEN solve it
7 0
3 years ago
I have a question here. ​
taurus [48]

9514 1404 393

Answer:

  P(F|A) = 35%

Step-by-step explanation:

P(F|A) = P(F&A)/P(A) = 7%/20% = 0.35

P(F|A) = 35%

_____

The given numbers will let you fill in a table for all of the categories of workers. However, it turns out this question can be answered using only the numbers given in the problem statement.

6 0
2 years ago
1. Consider the right triangle ABC given below.
lbvjy [14]
#1) 
A) b = 10.57
B) a = 22.66; the different methods are shown below.
#2)
A) Let a = the side opposite the 15° angle; a = 1.35.
Let B = the angle opposite the side marked 4; m∠B = 50.07°.
Let C = the angle opposite the side marked 3; m∠C = 114.93°.
B) b = 10.77
m∠A = 83°
a = 15.11

Explanation
#1)
A) We know that the sine ratio is opposite/hypotenuse.  The side opposite the 25° angle is b, and the hypotenuse is 25:
sin 25 = b/25

Multiply both sides by 25:
25*sin 25 = (b/25)*25
25*sin 25 = b
10.57 = b

B) The first way we can find a is using the Pythagorean theorem.  In Part A above, we found the length of b, the other leg of the triangle, and we know the measure of the hypotenuse:
a²+(10.57)² = 25²
a²+111.7249 = 625

Subtract 111.7249 from both sides:
a²+111.7249 - 111.7249 = 625 - 111.7249
a² = 513.2751

Take the square root of both sides:
√a² = √513.2751
a = 22.66

The second way is using the cosine ratio, adjacent/hypotenuse.  Side a is adjacent to the 25° angle, and the hypotenuse is 25:
cos 25 = a/25

Multiply both sides by 25:
25*cos 25 = (a/25)*25
25*cos 25 = a
22.66 = a

The third way is using the other angle.  First, find the measure of angle A by subtracting the other two angles from 180:
m∠A = 180-(90+25) = 180-115 = 65°

Side a is opposite ∠A; opposite/hypotenuse is the sine ratio:
a/25 = sin 65

Multiply both sides by 25:
(a/25)*25 = 25*sin 65
a = 25*sin 65
a = 22.66

#2)
A) Let side a be the one across from the 15° angle.  This would make the 15° angle ∠A.  We will define b as the side marked 4 and c as the side marked 3.  We will use the law of cosines:
a² = b²+c²-2bc cos A
a² = 4²+3²-2(4)(3)cos 15
a² = 16+9-24cos 15
a² = 25-24cos 15
a² = 1.82

Take the square root of both sides:
√a² = √1.82
a = 1.35

Use the law of sines to find m∠B:
sin A/a = sin B/b
sin 15/1.35 = sin B/4

Cross multiply:
4*sin 15 = 1.35*sin B

Divide both sides by 1.35:
(4*sin 15)/1.35 = (1.35*sin B)/1.35
(4*sin 15)/1.35 = sin B

Take the inverse sine of both sides:
sin⁻¹((4*sin 15)/1.35) = sin⁻¹(sin B)
50.07 = B

Subtract both known angles from 180 to find m∠C:
180-(15+50.07) = 180-65.07 = 114.93°

B)  Use the law of sines to find side b:
sin C/c = sin B/b
sin 52/12 = sin 45/b

Cross multiply:
b*sin 52 = 12*sin 45

Divide both sides by sin 52:
(b*sin 52)/(sin 52) = (12*sin 45)/(sin 52)
b = 10.77

Find m∠A by subtracting both known angles from 180:
180-(52+45) = 180-97 = 83°

Use the law of sines to find side a:
sin C/c = sin A/a
sin 52/12 = sin 83/a

Cross multiply:
a*sin 52 = 12*sin 83

Divide both sides by sin 52:
(a*sin 52)/(sin 52) = (12*sin 83)/(sin 52)
a = 15.11
3 0
3 years ago
Read 2 more answers
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