Question

Jewel is 7 years old and John is 16 years younger than Dave. One year ago, Dvae's age was twice the sum of Jewel's and John's ages. Fine the current age of each of them.

Answer 1

Answer:

Jewel is 7 years old

John is 1 year old

Dave is 17 years old

Step-by-step explanation:

From the question we are told that:

Jewel age is $J=7 years$

John age $J'=(D-16)years$

Dave's age a Year ago

 $D-1=2(J-1+J'-1)$

So that Dave.s age this Year could be

 $D=2((J-1)+(J'-1))+1$

Simplifying Equation for Dave's age we have

 $D=2((7)-1+(D-16)-1)+1$

 $D=2(6+D-15)+1$

 $D=2(D-9)+1$

 $D=2D-18+1$

 $D=17 Years$

Dave is 17 years old

Therefore

Johns age is

 $J'=(D-16)$

 $J'=17-16$

 $J'=1year old$

John is 1 year old