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inysia [295]
2 years ago
12

peter bought 32 chocolate bars at 4 for 3.he ate 2 of them and soldthe restat 3 for 4.how much money did he earn?

Mathematics
2 answers:
Naya [18.7K]2 years ago
6 0

cost: 32 bars*$3/4 bars = $24

ate 2  leaving 30 bars

30bars *$4/3 = 40 made

$40-$24= 16 profit

tester [92]2 years ago
6 0

To find how much he made in the end, called the profit, we are going to need to find the cost of all the expenditures and the revenue he makes.


First, let's find how much he spent to actually obtain the bars to sell. We know he bought 32 of the bars, at a price of 4 bars for 3 monetary units (monetary units just means units for money - an example would be dollars). He would have to purchase 8 of these deals to get 32 bars in total, so in total he spent 3 * 8 = 24 monetary units. This can be found through expressions as well, as shown below:

32 \textrm{bars} \cdot \dfrac{3 \,\textrm{monetary units}}{4 \,\textrm{bars}} = 8 \cdot 3 \,\textrm{monetary units} = 24 \,\textrm{monetary units}


Now, let's find how much money he made from selling the bars, or the revenue. First, he ate 2 of them, which he made no money from. So, he now has 30 bars which he can sell for a profit. He sold the rest of the bars at 3 bars for 4 monetary units. He sold 10 of these deals, which means he made 4 * 10 = 40 monetary units from all his sales. This can be solved using expressions, as shown below:

30 \,\textrm{bars} \cdot \dfrac{4 \,\textrm{monetary units}}{3 \,\textrm{bars}} = 10 \cdot 4 \,\textrm{monetary units} = 40 \,\textrm{monetary units}


To find his profit, or the money he made considering his expenditures, we are going to subtract the cost of all his expenditures from his revenue. Thus, his final profit is:

40 monetary units - 24 monetary units = 16 monetary units

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If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
2 years ago
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