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Valentin [98]
2 years ago
10

Solve for w. -9 – 7W = -9 – 8w

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
8 0

Answer:

Step-by-step explanation - w= o

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X2 + 8x + 6
Svetradugi [14.3K]
You could put the ‘+6’ at the start of the equation so it would read as +6(x2+8x) and then expand the bracket as you normally would so you would get x2x6 which would get you 12x and then 6x8x which would get you 48x and then you could group both numbers together as they’re like terms and your final answer would be 60x
6 0
2 years ago
Please help meeeee!!!!!!!!! What’s the answer????
uranmaximum [27]

Answer:

The answer would be y= |x-2| -1.

When graphing the answer B would be a larger quantity but A is the correct answer. Hope this helps :))

7 0
2 years ago
HELP PLEASEEE
jeka94

The exact circumference of the circle is 7 \frac{49}{150} k m

The approximate circumference of the circle is 7.33 k m

Explanation:

The diameter of the circle is 2 \frac{1}{3} \mathrm{km}

Now, we shall find the circumference of the circle.

The formula to determine the circumference of the circle is given by

C=\pi d

Where C is the circumference , \pi is 3.14 and d=2 \frac{1}{3} \mathrm is the diameter of the circle.

The exact circumference of the circle is given by

\begin{aligned}C &=\pi d \\&=(3.14)\left(2 \frac{1}{3}\right) \\&=(3.14)\left(\frac{7}{3}\right) \\&=\frac{21.98}{3}\end{aligned}

Multiply both numerator and denominator by 100, we get,

C=\frac{2198}{300} \\C=\frac{1099}{150}

Converting \frac{1099}{150} into mixed fraction, we get,

C=7 \frac{49}{150}

Thus, the exact circumference of the circle is 7 \frac{49}{150} k m

The approximate value of the circumference can be determined by dividing the value \frac{1099}{150}

C=\frac{1099}{150}=7.327

C=7.33km

Thus, the approximate circumference of the circle is 7.33 k m

3 0
3 years ago
HELP ASAP
klasskru [66]

Answer:

the answer is D. she loses 75

Step-by-step explanation:

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3 years ago
What is <br><br> 6 7/8 c = __ fl oz
masya89 [10]
The answer to this problem is
55 fl oz
6 0
3 years ago
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