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3 years ago

15

Solve the quadratic equation y^2-5y=-4 by factoring.

1 answer:

yan [13]3 years ago

8 0

$y^2-5y=-4\\
y^2-5y+4=0\\
y^2-y-4y+4=0\\
y(y-1)+4(y-1)=0\\
(y+4)(y-1)=0\\
y=-4 \vee y=1
$

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