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Grace [21]
4 years ago
7

If the three lines y= x+4 , 2y +x=2 and y= ax+8 are concurrent, find the value of a.​

Mathematics
1 answer:
Pepsi [2]4 years ago
4 0

Answer:

a=3

Step-by-step explanation:

Three or more lines in a plane  are said to be concurrent if they intersect at a single point.

First find the point of intersection of lines y=x+4 and 2y+x=2. Substitute y=x+4 into the second equation:

2(x+4)+x=2

2x+8+x=2

2x+x=2-8

3x=-6

x=-2

Then

y=-2+4=2

So, the point of intersection is (-2,2). The coordinates of this point must satisfy the equation of the third line, thus

2=a·(-2)+8

2=-2a+8

2a=8-2

2a=6

a=3

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DiKsa [7]

Answer: 6 years old.

Step-by-step explanation:

For this exercise let "x" represents your present age.

According to the information provided in the exercise, you know that  In three years, Chad will be three times your present age.

Then, your age in three years can be represented with the following expression:

x+3

Knowing at that time Chad's age will be three times yours and you will be half as old as old as Chad, you can write the following equation to represent this situation:

x+3=\frac{3x}{2}

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You get that this is:

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7 0
3 years ago
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statuscvo [17]
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3 years ago
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Elena-2011 [213]
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For example,
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3 years ago
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andrew-mc [135]
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