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dsp73
3 years ago
7

Use the formulas to generate a Pythagorean Triple with x = 5 and y = 2. The three side lengths, from smallest to largest are: a0

, a1, and a2.
Mathematics
2 answers:
stiv31 [10]3 years ago
8 0
<span>Perhaps you mean that for any integers x and y, x > y, x² - y², 2xy, and x² + y² form a Pythagorean triple. If GCF(x, y) = 1, the triple is primitive. For x = 5, y = 2, the triple is 21, 20, 29, or from smallest to largest, 20, 21, 29 ✠Let's just check 20² + 21² = 841= 29²</span>
Sliva [168]3 years ago
7 0

Answer:

Step-by-step explanation:

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How do you do inequalities
Alexandra [31]

Answer:

Summary Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own. But these things will change direction of the inequality: Multiplying or dividing both sides by a negative number. Swapping left and right hand sides

Step-by-step explanation:

6 0
2 years ago
What is the surface area of a rectangular box that is 12 centimeters long, 10 centimeters wide, and 15 centimeters high?
Harman [31]
SA= 2LW + 2LH + 2WH
Substituting for the values, SA = 900 cm^2
4 0
2 years ago
Which expression is equivalent to a^m divide a^n?(20points)
Citrus2011 [14]
<h3><u>Answer</u> :</h3>

\bigstar\:\boxed{\bf{\dfrac{a^m}{a^n}=a^{m-n}}}

<h3><u>Learn More</u> :</h3>

\dag\sf\:\:a^m\times a^n=a^{m+n}

\dag\sf\:\:\dfrac{a^m}{a^n}=a^{m-n}=\dfrac{1}{a^{n-m}}

\dag\sf\:\:a^{-m}=\dfrac{1}{a^m}

\dag\sf\:\:(a^{m})^n=a^{mn}

\dag\sf\:\:a^1=a

\dag\sf\:\:a^0=1

\dag\sf\:\:\sqrt[n]{a^m}=a^{\frac{m}{n}}

6 0
3 years ago
A medical clinic is reducing the number of incoming patients by giving vaccines before flu season. During week 5 of flu season,
kumpel [21]

Answer:

b) f(x)=-5x+100

Step-by-step explanation:

i guessed ngl.. but it was right.

7 0
3 years ago
Read 2 more answers
Give the next number in this unusual sequence: 2,3,7,25,121,721,5041,40321.
malfutka [58]

Answer:

362881

Step-by-step explanation:

The right sequence should be

2,3,7,25,121,721,5041,40321, 362881

Here, the formula used is a(n)=n!+1 where n=1 to infininity

n(1) =2=1!+1=2

n(2)= 3=2!+1=3

n(3)=7=3!+1=7

n(4)=25=4!+1=25

n(5)=121=5!+1=121

n(6)=721=6!+1=721

n(7)=5041=7!+1=5041

n(8)=40321=8!+1=40321

n(9)=362881=9!+1=362881

3 0
3 years ago
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