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2 years ago

What is the inequality shown in the graph?

Mathematics

2 answers:

dedylja [7]2 years ago

5 0

Your answer to the question is C i know this cause i had this question befor

Oliga [24]2 years ago

3 0

A and d are out and b says greater than 1 and thats incorrect so your answer should be c

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Show 1,700 using large cubes and flats

IgorC [24]

Answer:

How will the size of the model for 100,000 compare to the size of the model for 10,000? Possible answer: the pattern shows cube, long, flat, cube. So, the shape of the model for 10,000 will be long.

Step-by-step explanation:

3 0

3 years ago

I need all the spaces filled in please :)

Artist 52 [7]

Answer:

3x + y = -16

Step-by-step explanation:

Explanation:-

Given a system of equations are

5x+6y =-5

- 2x - 5y = -11

multiply '1' and Adding two system of equtions

+ 1 (5x + 6y = -5)

+ 1 ( -2x - 5y = -11)

3x + y = -16

Final answer:-

5x + 6y = -5

-2x - 5y = -11

3x + y = -16

7 0

3 years ago

Please help! (ignore the answer I chose)

Andrei [34K]

The numerator factors as (t-8)(t+4), so the whole thing is (t-8)(t+4)/(t-8). Now we can cancel the t-8 AS LONG as t isn't equal to 8, otherwise, we are canceling a zero from both numerator and denominator which is invalid. What is left is t+4.

So your choice was right.

5 0

3 years ago

The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20

drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, $P=P_0e^{bt}$

where, $P_0$ and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

$9600=P_0e^{b\times 0}$

So, $P_0=9600$

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

$18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\$

$\ln(23/12}=6b \\\\$

$b = \frac{\ln{1.92}}{6} \\\\$

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

$P=9600 \times e^{0.109\times t}$

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

$P=9600 \times e^{0.109\times 15}=49243$

Hence, the population of the rabbit in 2009 is 49243.

7 0

3 years ago

What is the solution of the system of equations? {4x−3y=152x+2y=4

trasher [3.6K]

Start by solving one equation for x or y, this time I'm choosing x. 2x = 4 - 2y, then x = 2 - y. Now substitute in x in the other equation. 4(2-y) - 3y = 15. This simplifies to 8 - 4y - 3y = 15. This simplifies to -7y = 7. Divide both sides by -7, and y = -1. Now plug the y value into the other equation: 2x + 2(-1) = 4. This simplifies to 2x = 6, and x = 3.
X = 3, Y = -1 or (3,-1)

8 0

2 years ago