I think its true...........................
Answer:
during January 2013. The charter authorized the following capital stock:
Preferred stock: 8 percent, par $10, authorized 20,000 shares.
Common stock: par $1, authorized 50,000 shares.
During 2013, the following transactions occurred in the order given:
a. Issued a total of 45,000 shares of the common stock for $20 per share.
b. Issued 12,000 shares of the preferred stock at $21 per share.
c. Issued 3,500 shares of the common stock at $25 per share and 1,200 shares of the preferred stock at $21.
d. Net income for the first year was $53,000.
Required:
Prepare the stockholders� equity section
The answer is the client is dissatisfied because measuring has nothing to do with weather the client likes the couch or not.
Answer:
r = 0.10666841 or 10.666841% rounded off to 10.67%
Explanation:
Using the constant growth model of dividend discount model, we can calculate the price of the stock today. The DDM values a stock based on the present value of the expected future dividends from the stock. The formula for price today under this model is,
P0 = D0* (1+g) / (r - g)
Where,
- D0 * (1+g) is dividend expected for the next period
- r is the required rate of return
By plugging in the available values for P0, D0 and g, we can calculate the value of r to be,
76.48 = 4.32 * (1+0.0475)/ (r - 0.0475)
76.48 * (r - 0.0475) = 4.5252
76.48r - 3.6328 = 4.5252
76.48r = 4.5252 + 3.6328
r = 8.158 / 76.48
r = 0.10666841 or 10.666841% rounded off to 10.67%
3.6 / 40 = g
g = 0.09 or 9%
Answer:
The 1st plant with a storage reservoir is a better option as compared to that of the 2nd plant.
Explanation:
Suppose the factor for variation in hourly demand is 2 So the average hourly demand is given as
Average Hourly Demand=Factor x Average Daily Demand
AHD=2 x 18000 m3
AHD=36000 m3
For the first pump
The Quantity in storage tank is 3975 m3
So the amount of pumping required is
For this value the pump will work for following hours
So the pump 1 can complete the demand of the town by working for 18.3 hours.
Now in order to complete the demand, the second pump is given as
For this the pump will work for as
So the pump 2 requires 16 hours to complete the demand of the town.
Here it is important to note that the realistic demand of the water can vary from the average value and thus when there is a drastic requirement of water in certain cases, the pump 2 will fail. Also pump 2 has to be run continuously and will produce excessive water which will be wasted if the hourly demand is less than that of the production value.
In context of this, the 1st plant with a storage reservoir is a better option as compared to that of the 2nd plant.
