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poizon [28]
3 years ago
7

Please please help asap

Mathematics
2 answers:
Irina18 [472]3 years ago
5 0

Simplify this by solving for t like you would in any other equation.

-4t≥28

<em>*Divide both sides by -4*</em>

t≥-7

<em>*When dividing or multiplying by a negative in an inequality, flip the sign*</em>

t≤-7

Hope this helps!!

MrMuchimi3 years ago
4 0

Answer:

bottom left,

Step-by-step explanation:

when you solve out the problem, that is the answer.

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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Minchanka [31]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the distance traveled by deluxe tire .

As per given , we have

Null hypothesis : H_0 : \mu \geq50000

Alternative hypothesis : H_a : \mu

Since H_a is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.

Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

s=sample standard deviation

For n= 31,\ \sigma=8000,\ \overline{x}=46,800\ \&\ s=46,800, we have

z=\dfrac{46800-50000}{\dfrac{8000}{\sqrt{31}}}=-2.23

By using z-value table,

P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23)   [∵P(Z≤-z)=1-P(Z≤z)]

=1-0.9871=0.0129

 Decision : Since p value (0.0129) < significance level  (0.05), so we reject the null hypothesis .

[We reject the null hypothesis when p-value is less than the significance level .]

Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.

4 0
3 years ago
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