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cricket20 [7]
3 years ago
12

Suppose that you had consumer group wanted to test to see if weight of participants in a weight loss program changed (up or down

). They computed a 95% confidence interval of the result (-4.977, 2.177). What do we know about the p-value for the test? Group of answer choices It would be less than 0.05. It would be greater than 0.05. It would be equal to 0.05. Can't be determined.
Mathematics
1 answer:
Basile [38]3 years ago
8 0

Answer:

Step-by-step explanation:

Hello!

The study variable is: X: the weight of a participant in a weight loss program

And the parameter of interest is μ: population average weight of participants of a weight loss program

Suppose that the hypothesis of interest is:

H₀: μ≥μ₀

H₁: μ<μ₀

α:0.05

To be able to determine the p-value you need:

The hypothesized value for the population mean (μ₀)

The distribution under witch the CI was constructed (either Z or t)

The sample size.

Given the computed 95%CI alone, the p-value cannot be determined.

I hope this helps!

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Divide the number of people selected by the total number of people.

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This means that 18% of the customers were selected for the survey.

If the probability is the same on Saturday, then we can multiply the expected customers by our .18

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7 0
3 years ago
The number of households without a computer at home in 2009 was closest to A)801000 B)1153000 C)1737000 D)3433000 E)4017000
bagirrra123 [75]

Answer:

B) 1153000

Step-by-step explanation:

Given

See attachment

Required

Number of households without computer in 2009

From the attachment, we have:

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So, the actual number is:

Number = p * n

Number = 22.3\% * 5170000

Number = 1152910

Number \approx 1153000

<em>Hence: (B) is correct</em>

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