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3 years ago

15

A junk box in your room contains a dozen old batteries, five of which are totally dead. You start picking batteries one at a tim

e and testing them. Find the probability of each outcome.

1 answer:

MArishka [77]3 years ago

6 0

Answer:

7/12 of a chance

Step-by-step explanation:

If you have 12 batteries and 5 are dead, 12 - 5 is 7, so there's going to be 7/12 of a chance.

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Copy and complete the table of each values for each equation

Aleksandr-060686 [28]

Step-by-step explanation:

Given function is y = –x.

Substitute the values of x in the function and find the values of y.

y = –x

At x = –2,

y = –(–2) = 2

At x = –1,

y = –(–1) = 1

At x = 0,

y = –(0) = 0

At x = 1,

y = –1(1) = –1

At x = 2,

y = –(2) = –2

Now, substitute the values of y in the table.

The image of the table is attached below.

8 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!

mrs_skeptik [129]

If you go from point (-1, -3) to point (4, 4), you can find the slope of the line using the slope formula. $m= \frac{4-(-3)}{4-(-1)}= \frac{7}{5}$ . So our slope is 7/5. The line goes through the y axis at -3/2, so putting that together we get an equation for the line that is $y= \frac{7}{5}x- \frac{3}{2}$ , choice D from above.

5 0

3 years ago

F(5)=3x+2 <br> What is the solution

Nady [450]

Answer:

f=3/5x+2/5c

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A right triangle has legs measuring 16 inches and 20 inches what is the length of the hypotenuse

leonid [27]

Answer:

The length of the hypotenuse is $4\sqrt{41}\ in$

Step-by-step explanation:

we know that

In a right triangle

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

c is the hypotenuse

a,b are the legs of the right triangle

substitute the values

$c^{2}=16^{2}+20^{2}$

$c^{2}=256+400$

$c^{2}=656$

$c=\sqrt{656}\ in$

Simplify

$c=4\sqrt{41}\ in$

8 0

3 years ago

Can you solve 27,28,39,30,31,32,33,34?

kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

$27. \: \: \frac{ {x}^{ - 1} }{ {x}^{ - 8} } \\ \frac{ {x}^{8} }{ {x}^{1} } \\ {x}^{8 - 1} = {x}^{7} \\$

$28. \: \: \: \frac{ {52x}^{6} }{ {13x}^{ - 7} } \\ \frac{ {52x}^{6} {x}^{7} }{13} \\ {4x}^{6 + 7} = {4x}^{13}$

$29. \: \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\ {f}^{( - 3) +2 + ( - 3) } \\ {f}^{ - 4} \\ \frac{1}{ {f}^{4} } \\$

$30. \: \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\ \frac{ {x}^{9} }{ {x}^{4} } \\ {x}^{9 - 4} = {x}^{5}$

$31. \: \: \frac{ {24x}^{6} }{ {12x}^{ - 8} } \\ \frac{ {24x}^{6} {x}^{8} }{12} \\ {2x}^{6 + 8} = {2x}^{14} \\$

$32. \: \: \frac{ {3x}^{2} {y}^{ - 3} }{ {12x}^{6} {y}^{3} } \\ \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3} {y}^{3} } \\ \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} } \\ \frac{ {x}^{ - 4} }{ {4y}^{6} } \\ \frac{1}{ {4y}^{6} {x}^{4} } = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }$

$33. \: \: {( {2x}^{3} {y}^{ - 3}) }^{ - 2} \\ {2x}^{3 \times - 2} {y}^{ - 3 \times - 2} \\ {2x}^{ - 6} {y}^{6} \\ \frac{ {2y}^{6} }{ {x}^{6} } \\ {( \frac{2y}{x} )}^{6} \\$

4 0

2 years ago