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Delvig [45]
2 years ago
14

Widget Indutries had stock that sold at 36 5/8 points. The stock rose 7 1/4 points. What is the new price?

Mathematics
1 answer:
vovangra [49]2 years ago
6 0

The new price of stock of Widget industries is 43 \frac{7}{8}

<u>Solution:</u>

Given that, Widget Industries had stock that sold at 36\frac{5}{8} points.  

The stock rose 7\frac{1}{4} points.  

We have find what is the new price of the stock ?

Now, we know that, new price of the stock will be combination of sold value of the stock and the new rise of points to the stock  

Then, new price of the stock = sold price of stock + rise in points

\text { New price of stock }=36 \frac{5}{8}+7 \frac{1}{4}

Converting the mixed fractions, we get

\begin{array}{l}{=\frac{38 \times 8+5}{8}+\frac{7 \times 4+1}{4}} \\\\ {=\frac{293}{8}+\frac{29}{4}=\frac{293}{8}+\frac{58}{8}=\frac{293+58}{8}=\frac{351}{8}=\frac{344+7}{8}=43 \frac{7}{8}}\end{array}

Hence, the new price of the stock is 43 \frac{7}{8}

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Answer:

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3 years ago
Soup ordinarily priced at 2 cans for .33 cents may be purchased in lots of one dozen for 1.74, what is the savings per a can whe
Sidana [21]

Answer:

Savings per can would be 0.02 cents when purchased in lots.

Step-by-step explanation:

Given:

Ordinary price of soup 2 cans = 0.33 cents.

When purchases in lots 12 cans = 1.74

We need to find the saving per can when purchased in Lots.

Solution:

Ordinary price of soup 2 cans = 0.33 cents.

1 can  = Cost of 1 can when purchased ordinary.

By Using Unitary method we get;

Cost of 1 can when purchased ordinary = \frac{0.33}{2} = 0.165\ cents/can

Now we will find the Cost of 1 can when purchased in lot.

12 cans = 1.74

1 can = Cost of 1 can when purchase in lot.

Again by using Unitary method we get;

Cost of 1 can when purchase in lot = \frac{1.74}{12} = 0.145\ cents/can

Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary

Savings = 0.165-0.145=0.02\ cents/can

Hence Savings per can would be 0.02 cents when purchased in lots.

5 0
3 years ago
The weight of an object on Venus is approximately 9/10 of its weight on Earth. The weight of an object
Sergeeva-Olga [200]

An object weighs 140 pounds more on Jupiter than it weighs on Venus. By simple algebraic operations, the required value is calculated.

<h3>What are the algebraic operations?</h3>

Addition, subtraction, multiplication, and division are the basic algebraic operations that are used for many computations.

<h3>Calculation:</h3>

It is given that,

An object's weight on Venus is approximately 9/10 of its weight on earth. I.e., WV = 9/10 WE

An object's weight on Jupiter is approximately 23/10 of its weight on earth. I.e., WJ = 23/10 WE

If an object weighs 100 pounds on earth, then

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WV = 9/10 × 100 = 90 pounds

The weight of the object on Jupiter is

WJ = 23/10 × 100 = 230

Thus, the difference between them is 230 - 90 = 140 pounds.

So, the object weighs 140 pounds more on Jupiter than on Venus.

Learn more about algebraic operations here:

brainly.com/question/24935016

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8 0
1 year ago
Use the Change of Base Formula to evaluate log5 92. Then convert log5 92 to a logarithm in base 3. Round to the nearest thousand
ANTONII [103]
I was thinking that the answer  could be 

2.810; log3 21.903
         
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<span> 2.810; log3 55.2 </span>

So,<span> log5 of 92 is between 2.5 and 3  Correct answer is A</span>

6 0
3 years ago
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Naddika [18.5K]

Answer:

9

Step-by-step explanation:

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