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Delvig [45]
2 years ago
14

Widget Indutries had stock that sold at 36 5/8 points. The stock rose 7 1/4 points. What is the new price?

Mathematics
1 answer:
vovangra [49]2 years ago
6 0

The new price of stock of Widget industries is 43 \frac{7}{8}

<u>Solution:</u>

Given that, Widget Industries had stock that sold at 36\frac{5}{8} points.  

The stock rose 7\frac{1}{4} points.  

We have find what is the new price of the stock ?

Now, we know that, new price of the stock will be combination of sold value of the stock and the new rise of points to the stock  

Then, new price of the stock = sold price of stock + rise in points

\text { New price of stock }=36 \frac{5}{8}+7 \frac{1}{4}

Converting the mixed fractions, we get

\begin{array}{l}{=\frac{38 \times 8+5}{8}+\frac{7 \times 4+1}{4}} \\\\ {=\frac{293}{8}+\frac{29}{4}=\frac{293}{8}+\frac{58}{8}=\frac{293+58}{8}=\frac{351}{8}=\frac{344+7}{8}=43 \frac{7}{8}}\end{array}

Hence, the new price of the stock is 43 \frac{7}{8}

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Answer:

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Step-by-step explanation:

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Add ( half the coefficient of the x- term )² to x² + 28x

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ANSWER AND EXPLAIN PLEASE ILL MARK BRAINLIEST!!!!!!!!!!!
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Answer:

x = 1 and y = -2

Step-by-step explanation:

Given that,

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3 years ago
The time for a visitor to read health instructions on a Web site is approximately normally distributed with a mean of 10 minutes
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Answer:

a) The mean is 10 and the variance is 0.0625.

b) 0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c) 10.58 minutes.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with a mean of 10 minutes and a standard deviation of 2 minutes.

This means that \mu = 10, \sigma = 2

Suppose 64 visitors independently view the site.

This means that n = 64,  = \frac{2}{\sqrt{64}} = 0.25

a. The expected value and the variance of the mean time of the visitors.

Using the Central Limit Theorem, mean of 10 and variance of (0.25)^2 = 0.0625.

b. The probability that the mean time of the visitors is within 15 seconds of 10 minutes.

15 seconds = 15/60 = 0.25 minutes, so between 9.75 and 10.25 seconds, which is the p-value of Z when X = 10.25 subtracted by the p-value of Z when X = 9.75.

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Z = \frac{X - \mu}{s}

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Step-by-step explanation:

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