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Romashka [77]
2 years ago
9

Juan examines the sequence 1, 3, 4, 7, 11, . . . and draws the conclusion that the next number in the sequence is 18. Which stat

ements regarding the situation are accurate? Check all that apply.
Juan used inductive reasoning.
Juan's conclusion is a conjecture.
Juan's conclusion is not possible.
Juan's conclusion is a counterexample.
Juan based his conclusion on patterns.
Mathematics
1 answer:
Vlada [557]2 years ago
4 0

Answer:

Juan conclusion is counterexample

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Answer:

There is not enough evidence to suggest that mean starting salary of a graduate with a bachelor in economics is different from $48,500.

Step-by-step explanation:

In this case we need to test whether the mean starting salary of a graduate with a bachelor in economics is $48,500.

The information provided are:

\bar x=\$43350\\s=\$15000\\n=50\\\alpha =0.01

The hypothesis for the test can be defined as follows:

<em>H</em>₀: The mean starting salary of a graduate with a bachelor in economics is $48,500, i.e. <em>μ</em> = 48500.

<em>Hₐ</em>: The mean starting salary of a graduate with a bachelor in economics is different from $48,500, i.e. <em>μ</em> ≠ 48500.

As the population standard deviation is not known we will use a t-test for single mean.

Compute the test statistic value as follows:

 t=\frac{\bar x-\mu}{s/\sqrt{n}}

   =\frac{43350-48500}{15000/\sqrt{50}}\\\\=-2.42773\\\\\approx -2.43

Thus, the test statistic value is -2.43.

Compute the p-value of the test as follows:

 p-value=2\times P(t_{49}>-2.43)=0.0188

*Use a t-table.

Thus, the p-value of the test is 0.0188.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

p-value = 0.0188 > α = 0.01

The null hypothesis will not be rejected at 1% level of significance.

Thus, concluding that there is not enough evidence to suggest that mean starting salary of a graduate with a bachelor in economics is different from $48,500.

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