1.29
One assignment a day and a little bit on another
Explanation:
Provided <u>2 length sides</u> and <u>one angle</u> also need to find <u>one missing side</u>.
So, use cosine rule:
a² = b² + c² - 2bc cos(A)
<h3><u>Part 1</u></h3>
c² = 9² + 11² - 2(11)(9) cos(57)
c² = 94.16147
c = √94.16147 = 9.70 cm
<h3><u>Part 2</u></h3>
d² = 5² + 7² - 2(5)(7) cos(48)
d² = 27.16
d = √27.16 = 5.21
<h3><u>Part 3</u></h3>
5² = 7² + 9² - 2(7)(9) cos(H)
-126cos(H) = 25 - 49 - 81
cos(H) = -105/-126
cos(H) = 5/6
H = cos⁻¹(5/6) = 33.56°
<h3><u>Part 4</u></h3>
8² = 4² + 7² - 2(4)(7) cos(J)
-56cos(J) = 64 - 16 - 49
cos(J) = -1/-56
J = cos⁻¹(1/56) = 88.98°
Passcode: 3142
10y + 7 + 3(3y + 7) = 180
10y + 7 + 9y + 21 = 180
19y + 28 = 180
19y = 180 - 28
19y = 152
y = 152/19
y = 8
Plug back into Q and S.
Q = 10y + 7
Q = 10(8) + 7
Q = 80 + 7
Q = 87
S = 3(3y + 7)
S = 9y + 21
S = 9(8) + 21
S = 72 + 21
S = 93
Without solving for x to find the other angles, we can easily see that the answer is choice C.
Answer:
P = 61°
Q = 87°
R = 119°
S = 93°
Done!
Answer:
<h2>
Function is
y = x.</h2><h2>
Domain: 
.</h2><h2>
Range: 
.</h2>
Step-by-step explanation:
In the given image, the line passes through (-1, -1) and (1, 1).
Let the equation of the line is 
, where m is the tangent of the line and c is a constant.
Putting the co-ordinates of the points in the equation, we get 
and 
From the two equations we get, c = 0 and m = 1.
Hence, the function is y = x.
Domain is .
Range is
Step-by-step explanation:
