Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:


I'm going to solve
for x using the quadratic formula:







Let's see if uv=u+v holds.

Keep in mind you are multiplying conjugates:



Let's see what u+v is now:


We have confirmed uv=u+v for k=2.
48x + 35
x = 2
plug in 2 for x
48(2) + 35
multiply 2 and 48 together
48 x 2 = 96
add the product (96) with 35
96 + 35 = 131
answer is 131
131 is your answer
hope this helps
Well, 5384 is 5000 bigger than 384. So you would add 20000 (4*5000) to the answer of 4*384, which is 1536.
So 1536+20000=21536
Answer:
(8,3)
Step-by-step explanation:
Edge 2020 hope this helps =)
15-6x2=X im not sure if thats right but its what i got