4 is a coefficient and X and Y are variables so the -110 is the constant so there for the answer is D
<span><span>I think the answers are:
Statement Reason</span><span><span><span>
<span>12=<span>13</span>x+5 </span></span>Given</span><span><span>
<span>7=<span>13</span>x </span></span>Subtraction Property of Equality</span><span><span>
21 = x </span>Multiplication Property of Equality</span><span><span>
x = 21 </span><span>Symmetric Property of Equality
By the way, I'm doing the same exam for Geometry as well. There's a lot of proof questions on there which I'm not good at doing for the reasoning part. If you finish the exam before I do, maybe you can message me what the answers are for some of the questions on there so I know if my answers for the questions are incorrect or not.
Besides that, hope the answer above is correct for you.
<em>~ ShadowXReaper069</em></span></span></span></span>
Answer:
recursive: f(0) = 7; f(n) = f(n-1) -8
explicit: f(n) = 7 -8n
Step-by-step explanation:
The sequence is an arithmetic sequence with first term 7 and common difference -8. Since you're numbering the terms starting with n=0, the generic case will be ...
recursive: f(0) = first term; f(n) = f(n-1) + common difference
explicit: f(n) = first term + n·(common difference)
To get the answer above, fill in the first term and common difference values.
I think its (B)
V = four-thirds pi r cubed = Four-thirds (3.14) (5) cubed
Answer:
Two complex roots.
Step-by-step explanation:
F(x)=2x^4 +5x^3 - x^2 +6x-1
is a polynomial in x of degree 4.
Hence F(x) has 4 roots. There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.
Use remainder theorem to find the roots of the polynomial.
F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0
There is a change of sign in F from 0 to 1
Thus there is a real root between 0 and 1.
Similarly by trial and error let us find other real root.
F(-3) = -1 and F(-4) = 94
SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.
Other two roots are complex roots since no other place F changes its sign
