Answer: C) 75%
Step-by-step explanation:
Let G represents the event of having garbage in houses and F represents the event of houses having fenced in backyard.
Given: In neighborhood , the probability of houses have a garage and a fenced in backyard ![P(G\cap F)= 60\%=0.6](https://tex.z-dn.net/?f=P%28G%5Ccap%20F%29%3D%2060%5C%25%3D0.6)
The probability of houses have a garage P(G)=80%=0.8
The probability that a house has a fenced in backyard given that it has a garage is given by :-
![P(F|G)=\dfrac{P(G\cap F)}{P(G)}\\\\\Rightarrow\ P(F|G)=\dfrac{0.6}{0.8}=0.75](https://tex.z-dn.net/?f=P%28F%7CG%29%3D%5Cdfrac%7BP%28G%5Ccap%20F%29%7D%7BP%28G%29%7D%5C%5C%5C%5C%5CRightarrow%5C%20P%28F%7CG%29%3D%5Cdfrac%7B0.6%7D%7B0.8%7D%3D0.75)
In percent, ![0.75\times100=75\%](https://tex.z-dn.net/?f=0.75%5Ctimes100%3D75%5C%25)
Hence, the probability that a house has a fenced in backyard given that it has a garage = 75%.