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Mandarinka [93]

3 years ago

5

What is nine? Huhhhhhhhhhhh?

2 answers:

grigory [225]3 years ago

7 0

Step-by-step explanation: The base of the power in the original equation becomes the base of the log. So we have $^{log}3$ .

Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.

So we have $^{log} 3$ $9 = 2$ which is 3² = 9 written in logarithmic form.

This can also be switched around to read $2 = ^{log} 3 = 9$ .

So the first choice will be your answer.

My work is also show in the image attached,

I just didn't switch it.

Rudiy273 years ago

4 0

Answer:

Step-by-step explanation:

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In need help in this

Lyrx [107]

Answer:

Vertex form is

$a(x - h) {}^{2} + k = y$

where (h,k) is the vertex

So our vertex form is

$a(x - 3) {}^{2} + 5 = y$

It passes through (6,0) so we have

$a(6 - 3) {}^{2} + 5 = 0$

Solve for a.

$a(3) {}^{2} + 5 = 0$

$a(9) = - 5$

$a = \frac{ - 5}{9}$

So our equation is

$- \frac{5}{9} (x - 3) {}^{2} + 5$

7 0

3 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

<em>The correct option is C.</em>

Step-by-step explanation:

<u>Root Of Complex Numbers</u>

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

8 0

3 years ago

Can anyone help me with geometry

maxonik [38]

Angle = 0.08 * 360 = 28.8 degrees

8 0

3 years ago

How many meters of wrapping paper is needed to cover a present of this shape?

sattari [20]

Answer:

what are the options????

4 0

3 years ago

Read 2 more answers

35 POINT QUESTION, WILL MARK BRAINLIEST. Which of the following options is a 3rd degree polynomial with exactly 1 real root?

Romashka [77]

Answer:

A. F(x) = x^3+9x^2+27x+27

Step-by-step explanation:

I am not 100% sure but I think this is right.

I found the root for this equation: x=-3

Hope this helps!

5 0

3 years ago

Read 2 more answers