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2 years ago

What is nine? Huhhhhhhhhhhh?

Mathematics

2 answers:

grigory [225]2 years ago

7 0

Step-by-step explanation: The base of the power in the original equation becomes the base of the log. So we have $^{log}3$ .

Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.

So we have $^{log} 3$ $9 = 2$ which is 3² = 9 written in logarithmic form.

This can also be switched around to read $2 = ^{log} 3 = 9$ .

So the first choice will be your answer.

My work is also show in the image attached,

I just didn't switch it.

Rudiy272 years ago

4 0

Answer:

Step-by-step explanation:

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What is the period of y=3cot(4x−3π)

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Hello!

hint: we can rewrite your function as below:

3/tan(4x−3π) = 3(1+tan4xtan3π)/tan4x−tan3π =

=3/tan(4x) = 3cot(4x)

now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

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Hope this Helps! Have A Wonderful Day! :)

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