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2 years ago

Solve the quadratic inequalities, by either graphing, or pure algebraic method:

Mathematics

1 answer:

BlackZzzverrR [31]2 years ago

6 0

Answer:

less than/equal to -2

Or, greater than/equal to 2.5

Step-by-step explanation:

2x² - x - 10 ≥ 0

2x² - 5x + 4x - 10 ≥ 0

x(2x - 5) + 2(2x - 5) ≥ 0

(x + 2)(2x - 5) ≥ 0

Roots: -2, 5/2

x《 -2 or x》5/2

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2 years ago

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2 years ago

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Andreyy89

Answer:

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Step-by-step explanation:

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2 years ago

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miskamm [114]

Answer:

2 and - $\frac{1}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

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Parallel lines have equal slopes, thus

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3 0

3 years ago

(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$

Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.

$\displaystyle \large{- 10i+ 45 - (2 - 3i)} \\ \displaystyle \large{- 10i+ 45 - 2 + 3i}$

Combine like terms.

$\displaystyle \large{43 - 7i}$

5 0

2 years ago