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Viktor [21]
3 years ago
8

Use technology and the given confidence level and sample data to find the confidence interval for the population mean muμ. assum

e that the population does not exhibit a normal distribution. weight lost on a diet:weight lost on a diet: 99 % confidence 99% confidence n equals 61n=61 x overbar equals 2.0 kgx=2.0 kg s equals 4.8 kg
Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

The given in this problem are:

99% confidence level

N = 61

Mean = 2.0 kg

Standard deviation = 4.8

Z value for a 9% confidence interval is 2.576

 

Confidence Interval = mean ± Z s/ sqrt n

= 2.0 ± 2.576(4.8/sqrt 61)

=2.0 ± 2.576 (0.6145770236779006736364371988794)

= 2.0 ± 1.5832

<span>= 0.4168 < x < 3.5832</span>

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