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Maurinko [17]
3 years ago
6

A coin is loaded so that the probability of heads is 0.55 and the probability of tails is 0.45. suppose the coin is tossed twice

and the results of the tosses are independent. what is the probability of obtaining exactly one head?
Mathematics
1 answer:
Vladimir79 [104]3 years ago
8 0
The probability is 0.235
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Find the measurements of the numbered angles in each isosceles trapezoid.
SSSSS [86.1K]

Answer:

∠1 = 96°

∠2 = 84°

∠3 = 84°

Step-by-step explanation:

∠1 = 96°

∠2 = ∠3

∠1 + 96 + ∠2 + ∠3 = 360°

∠2 = (360 - 96 - 96)/2 = 84°

∠3 = 84°

8 0
3 years ago
Can anyone solve 9, 10, 11, 12, and 13 I'm stuck on those problems, I already solved 14, 15, and 16 on paper.
ddd [48]

Answer:

9. x>-4 or x≥1

10. a<2 or a≥-5

11. v≤7 or v≥-4

12. k≥5 or k<8

13. n>6.8 and n≤9

Step-by-step explanation:

9. -2x-7>1

-2x>8

x>-4

x-2≥-1

x≥1

10.a/-2 <-1

a<2

-4a+3≥23

-4a≥20

a≥-5

11. 6v+38≤-4

6v≤-42

v≤7

2(v+3)≥-2

2v+6≥-2

2v≥-8

v≥-4

12. 4(1-k)≥-16

4-4k≥-16

-4k≥-20

k≥5

7-6k<-41

-6k<-48

k<8

13. 10n-9>-59

10n>-68

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4 0
2 years ago
PLSSS HLEPP ME OUTT ITS URGENTTTT​
Step2247 [10]

Answer:

Step-by-step explanation:

(1860-11)=1849

√(1849) = 43

(A quick trial)

7 0
2 years ago
In a recent survey of 974 voters, 724 indicated that they were in favor of a new city park, while the other 250 voters said that
Marrrta [24]
250/974 = x/40,000...250 opposed to 974 total = x opposed to 40,000 total
cross multiply because this is a proportion
974x = 10,000,000
x = 10,000,000/974
x = 10266.94 rounds to 10,267 <==
3 0
3 years ago
Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.​
Galina-37 [17]

Question:

Prove that:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Answer:

Proved

Step-by-step explanation:

Given

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Required

Prove

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Subtract tan(10) from both sides

- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

Factorize the right hand size

tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)

Rewrite as:

tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))

Divide both sides by 1-tan(70). tan(100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)

In trigonometry:

tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}

So:

\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)} can be expressed as: tan(70 + 100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10) gives

tan(70 + 100) = -tan(10)

tan(170) = -tan(10)

In trigonometry:

tan(180 - \theta) = -tan(\theta)

So:

tan(180 - 10) = -tan(10)

Because RHS = LHS

Then:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) has been proven

6 0
3 years ago
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