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3 years ago

6

A coin is loaded so that the probability of heads is 0.55 and the probability of tails is 0.45. suppose the coin is tossed twice

and the results of the tosses are independent. what is the probability of obtaining exactly one head?

1 answer:

Vladimir79 [104]3 years ago

8 0

The probability is 0.235

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For the piecewise Function below, which of the following statments is true? Someone please help me

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The first one and the third one are correct. because for the when you plug 1 on the first piece wise function you get 3.

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Estimate 4281+7028 by first rounding each number to the nearest thousand.

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Write 4 dollars, 8 dimes, and 2 pennies with dollar sign and a decimal point

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Answer:

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What is the surface area of a cube in which each face of the cube has an area of 7 cm2? surface area = a0 cm2?

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HELP!! I NEED THIS QUICKLY

Elza [17]

Answer:

A and D

Step-by-step explanation:

We are given that

(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)

$x_1=\frac{3}{4}$

$y_1=\frac{2}{3}$

$x_2=\frac{1}{4},y_2=1$

$x_3=1,y_3=\frac{1}{2}$

$x_4=\frac{1}{2},y_4=1$

k= $\frac{1}{2}$

Direct proportion:

$\frac{x}{y}=k$

Inverse proportion: $xy=k$

$\frac{x_1}{y_1}=\frac{3}{4}\times \frac{3}{2}=\frac{9}{8}\neq \frac{1}{2}$

Therefore, it is not in direct proportion.

$\frac{1}{4\times 2}=\frac{1}{8}\neq\frac{1}{2}$

$\frac{1}{\frac{1}{2}}=2\neq \frac{1}{2}$

$x_1y_1=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}$

$x_2y_2=\frac{1}{4}\times 2=\frac{1}{2}$

$x_3y_3=1\times \frac{1}{2}=\frac{1}{2}$

$x_4y_4=\frac{1}{2}\times 1=\frac{1}{2}$

Therefore, $xy=k=\frac{1}{2}$

Hence, the given points form an inverse variation .

$xy=\frac{1}{2}$

$y=\frac{1}{2x}$

Option A and D is true.

6 0

3 years ago