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lesya692 [45]
3 years ago
5

The late fee for library books is 2.00 plus 15c each day for a book that is late.if Monica's late fee is 2.75 write and slove a

linear equation to find how many days late her book is
Mathematics
1 answer:
sergeinik [125]3 years ago
3 0
X=2.00+15x
2.75=2.00+15x
-2.00  -200
75=15x
Divide each side by 15
x=5
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Diabetic needs to calculate the amount of carbs in a meal to determine how much insulin to give
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Step-by-step explanation:

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3 years ago
Guess the rule and add the next number in the sequence.<br> 6, 8, 12, 18, 26,
brilliants [131]

Answer:

The rule: Adds twice as much as the previous number added

Next number: 38

Step-by-step explanation:

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2 years ago
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Which is greater 3yd or 30ft
Volgvan

Answer: 30 feet is greater

Step-by-step explanation:

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3 years ago
All the cubes root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%20%2B%20i%7D%20" id="TexFormula1" title=" \sqrt{3 + i
melisa1 [442]

If you're looking for the cube roots of √(3 + <em>i </em>), you first have to decide what you mean by the square root √(…), since 3 + <em>i</em> is complex and therefore √(3 + <em>i </em>) is multi-valued. There are 2 choices, but I'll stick with 1 of them.

First write 3 + <em>i</em> in polar form:

3 + <em>i</em> = √(3² + 1²) exp(<em>i</em> arctan(1/3)) = √10 exp(<em>i</em> arctan(1/3))

Then the 2 possible square roots are

• √(3 + <em>i</em> ) = ∜10 exp(<em>i</em> arctan(1/3)/2)

• √(3 + <em>i</em> ) = ∜10 exp(<em>i</em> (arctan(1/3)/2 + <em>π</em>))

and I'll take the one with the smaller argument,

√(3 + <em>i</em> ) = ∜10 exp(<em>i</em> arctan(1/3)/2)

Then the 3 cube roots of √(3 + <em>i</em> ) are

• ∛(√(3 + <em>i</em> )) = ¹²√10 exp(<em>i</em> arctan(1/3)/6)

• ∛(√(3 + <em>i</em> )) = ¹²√10 exp(<em>i</em> (arctan(1/3)/6 + <em>π</em>/3))

• ∛(√(3 + <em>i</em> )) = ¹²√10 exp(<em>i</em> (arctan(1/3)/6 + 2<em>π</em>/3))

On the off-chance you meant to ask about the cube roots of 3 + <em>i</em>, and not √(3 + <em>i </em>), then these would be

• ∛(3 + <em>i</em> ) = ⁶√10 exp(<em>i</em> arctan(1/3)/3)

• ∛(3 + <em>i</em> ) = ⁶√10 exp(<em>i</em> (arctan(1/3)/3 + 2<em>π</em>/3))

• ∛(3 + <em>i</em> ) = ⁶√10 exp(<em>i</em> (arctan(1/3)/6 + 4<em>π</em>/3))

3 0
3 years ago
A rectangular field has an area 28800 sq meter. Its length is twice as long as its width. What is the length of its sides?
mina [271]
W= width L= length = 2W

Area of Rectangle= Length * Widthsubstitute the area and the value of L in the formula
28,800 m^2= 2W * W
28,800= 2W^2divide both sides by 2 in an effort to isolate the variable w
14,400= W^2take the square root of both sides
√14,400= W^2
we want the negative and positive root of the radicand (the number under the radical symbol - 14,400 in this case)
120= w OR -120= w


LENGTHL= 2W= 2(120)= 240 meters

ANSWER: The side lengths are W= 120 m; L= 240 m.  Even though W= -120 too, it is not a valid solution in this case since a field cannot have a negative value.

Hope this helps!  :)
3 0
3 years ago
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