2k - 4 = 2 + k
(Subtract both sides by k)
k - 4 = 2
(Add both sides by 4)
k = 6
$16 is the answer
Maybe I’m actually not sure
it isn't possible to just give extra points in a simple and reliableway. anyways, let's starts.
a. is simple, just put the terms in order
r² +6r -5
because:
![{r}^{2} + {6r}^{1} + {5r}^{0}](https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B2%7D%20%20%2B%20%20%7B6r%7D%5E%7B1%7D%20%20%2B%20%20%7B5r%7D%5E%7B0%7D%20)
anything to the power of 0 equals 1,
because it's the same as r/r, and 5 * r/r = 5*1
b. same logic as above
a²b² -5ab +33
c.
-c³ +ab +d +9
d.
-9y^5 - 2x³y²z +4x² +10x +1
^5 = to the power of five, it's the fastest way to type it without the special math input tool.
hope it helps you
7.) 4 (-2) 12 I multiply 4 by -2 which gives me
-8 = 12 so it is a no solution
8.) 39 - 3 = -6 (4-3)
first u want to multiply the -6 by four and the -6 by the -3 which gives you :
39 - 3 = -24 + 18
36 = -6
this is also a no solution