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elena-s [515]
3 years ago
9

You are randomly drawing marbles from a bag containing both blue and green marbles, without replacing the marbles between draws.

If B = blue and G = green, which of the following represents the probability of drawing a blue marble on the first draw and a green marble on the second?
A. P(B) • P(G)
B. P(B and G)
C. P(G after B)
D. P(B, then G)

You are randomly drawing marbles from a bag containing 4 blue and 2 green marbles, replacing the marbles between draws. Which of the following will give the probability of drawing a blue marble on both your first and second draws?
A. 1 over 4 • 1 over 4
B. 4 over 6 • 4 over 6
C. 1 over 4 • 1 over 3
D. 4 over 6 • 3 over 6
Mathematics
1 answer:
arlik [135]3 years ago
6 0
The answer is A to the first one and D to the second one
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Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that
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Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

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This gives

k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}

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k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

brainly.com/question/14285697

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