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3 years ago

6

I need help because I didn't understand and I don't know how to do and I don't know plz help me and if you help me I would like

to thank you

1 answer:

zepelin [54]3 years ago

3 0

Umm what do you need helo with?

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Use the given graph. Determine the period of the function.

Ivahew [28]

Answer:

3

Step-by-step explanation:

Period of a function is the period after which the function attains the same value

in the graph attached with this problem we can see that

f(0)=1

the value of x for which function f(x) attains the value 1 again is at

x=3

f(3)=1

similarly , we see

f(6)=1 , f(9)=1

Hence we see that after every increased value of x by 3 units , we attain the same value of function . hence the period of the function is 3

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3 years ago

Mr. Cannon has a piece of land that is 3/7 of an acre. He wants to build 10 houses on his land. How much land does each house ge

sashaice [31]

Answer:

Step-by-step explanation:

3/7 divided by 10 houses= 0.042 acres per house

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3 years ago

Kyle ran 5.4 miles on each of four days this week. He ran 7 miles on the fifth day. How many miles did Kyle run this week?

77julia77 [94]

That would be

4*54 + 70 = 286 miles Answer

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3 years ago

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(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

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2 years ago

Nicki school day last 7 hours 20 minutes how many minutes does Nicki school day last explain how you found your answer

VLD [36.1K]

7 hours X 60 minutes = 420 minutes

420 minutes + 20 minutes = 440 minutes

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3 years ago

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