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BaLLatris [955]
2 years ago
14

PLEASE HELPPPPP CLICK THE SCREENSHOT FOR THE QUESTION

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
7 0
44-2*5=34
44+3*5=59
See the photo

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Will give brainliest
lianna [129]

Answer:

40⁰

Step-by-step explanation:

<em><u>Main</u></em><em><u> </u></em><em><u>principles</u></em><em><u>:</u></em>

1.Alternate angles equal

2.Vertically opposite angles are equal

If angle 2 is 40⁰, then using the second principle,angle 3 is also 40⁰

Then, using the first principle,(alternate angles/angles that form any variation of "z"), angle 6 is also 40⁰.

There are other ways to do this like using co-interior angles, straight angles and other methods, these are the easiest to understand

6 0
3 years ago
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At a pet store, Davina counted 12 parrots out of 20 birds. Which is an equivalent ratio of parrots to birds at the pet store? 2:
Mazyrski [523]

Answer:

3 to 2

Hope it helps xD

3 0
3 years ago
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How do you simplify <br> 2i&lt;6u?
Stels [109]
2(i<3u) is the answer to your problem



4 0
3 years ago
1. Consider a lottery with three possible outcomes:-$125 will be received with probability 0.2-$100 will be received with probab
Norma-Jean [14]

Answer:

The expected value of the lottery is $80

Step-by-step explanation:

To get the expected value, we have to multiply each outcome by its probability

Then we proceed to add up all of these to get the expected value of the lottery

we have this as ;;

125(0.2) + 100(0.3) + 50(0.5)

= 25 + 30 + 25 = $80

3 0
3 years ago
Poker is a card played with a standard 52 card playing deck. We draw one card at a time without replacement from the top of a sh
Maru [420]

Answer:

Step-by-step explanation:

Given that Poker is a card played with a standard 52 card playing deck. We draw one card at a time without replacement from the top of a shuffled standard poker deck and stop when we draw an ace.

There are 4 aces and 48 non aces.

For randomly drawing card for first card we have probability for drawing ace = 4/52 and non ace = 48/52

X = no of cards we have drawn

If X is the total no of cards drawn, then the event should have been

first x-1 cards non aces, and the last card ace.

Hence P(X)

= Drawing x-1 cards from 48 non aces * drawing one card from remaining 52-(x-1) cards

= \frac{48C(x-1)}{52C(x-1)} *\frac{4}{53-x} \\, x=1,2,.....49

5 0
3 years ago
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