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morpeh [17]
3 years ago
6

A student received an 82% on an exam. If there were 50 questions on the exam, which ratio would show the number of questions ans

wered correctly to the total number of questions? A. 25:50 B. 59:50 C. 82:50 D. 41:50
Mathematics
2 answers:
solmaris [256]3 years ago
8 0
Hello!

To solve this we have to find what 82% of 50 is

So we do 50 * 0.82 where 0.82 is 82% as a decimal.

This gives us 41

So the answer is D

Hope this helps!
Oksana_A [137]3 years ago
8 0
Total questions = 50
Correct Answer = 82% x 50 = 0.82 x 50 = 41

Ratio of questions answered correctly to total number of questions:
41 : 50 

--------------------------------------------
Answer: 41 : 50 (Answer D)
--------------------------------------------
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The Slow Ball Challenge or The Fast Ball Challenge.
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Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

Pitches = 7

P(Hit) = 80\%

Win = \$60

Lost = \$10

Fast Ball Challenge

Pitches = 3

P(Hit) = 70\%

Win = \$60

Lost = \$10

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 7 --- pitches

x = 7 --- all hits

p = 80\% = 0.80 --- probability of hit

So, we have:

P(x) =^nC_x * p^x * (1 - p)^{n - x}

P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}

P(7) =1 * 0.80^7 * (1 - 0.80)^0

P(7) =1 * 0.80^7 * 0.20^0

Using a calculator:

P(7) =0.2097152 --- This is the probability that he wins

i.e.

P(Win) =0.2097152

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 -0.2097152

P(Lose) = 0.7902848

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.2097152 * \$60 + 0.7902848 * \$10

Using a calculator, we have:

Expected = \$20.48576

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 3 --- pitches

x = 3 --- all hits

p = 70\% = 0.70 --- probability of hit

So, we have:

P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}

P(3) =1 * 0.70^3 * (1 - 0.70)^0

P(3) =1 * 0.70^3 * 0.30^0

Using a calculator:

P(3) =0.343 --- This is the probability that he wins

i.e.

P(Win) =0.343

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 - 0.343

P(Lose) = 0.657

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.343 * \$60 + 0.657 * \$10

Using a calculator, we have:

Expected = \$27.15

So, we have:

Expected = \$20.48576 -- Slow ball

Expected = \$27.15 --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

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