Question

can somebody help me simplify this given radical to the lowest form√112a^2 and try to explain it to me in layman's terms

Answer 1

$\bf \sqrt{112a^2}~~ \begin{cases} 112=2\cdot 2\cdot 2\cdot 2\cdot 7\\ \qquad 2^2\cdot 2^2\cdot 7\\ \qquad (2^2)^2\cdot 7 \end{cases}\sqrt{(2^2)^2\cdot 7\cdot a^2}\implies 2^2a\sqrt{7}\implies 4a\sqrt{7}$