Answer:
The probability that 6 or more women would be laid off is P=0.08.
Step-by-step explanation:
In this case, we have a group of people and a proportion of women and men. We can think of the people laid off as a random sample taken from the population (all employees of the department).
The right model to represent that is with a binomial distribution. In this case, the sample size is n=8 and the probability of picking a woman is p=0.44.
According to this model, the probability that 6 or more women, out of 8 persons, would be laid off is:
Answer:
300 pounds
Step-by-step explanation:
2,000 - 500 = 1,500
1,500 / 5 = 300
300 pounds of sand can be put into each of the 5 smaller sandboxes
Let b>a,
a+b=40 so we can say a=40-b
We are told that b-a=6.5, using a found above in the equation gives us:
b-(40-b)=6.5
b-40+b=6.5
2b-40=6.5
2b=46.5
b=23.25, and since a=40-b
a=40-23.25
a=16.75
So a=16.75 and b=23.25
check...
16.75+23.25=40, 40=40
23.25-16.75=6.5, 6.5=6.5
Normal or natural variations in the quality of production output that are due purely to chance are common causes.
According to the statement
we have to tell about the that cause which effect the quality and production output in the normal and natural variation.
So, For this purpose, we know that the
Common cause variation is present when the control chart of a process measure shows a random pattern of variation with all points within the control limits. When a control chart shows common cause variation, a process measure is said to be in statistical control or stable.
And due to this cause there is a lot of effect on the natural variations in the quality of production output.
So, Normal or natural variations in the quality of production output that are due purely to chance are common causes.
Learn more about common cause variation here
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Answer:
Step-by-step explanation:
We want to find angle DEB. We know AB is perpendicular to AC, CD is congruent to CE and angle B is 48 degrees.
ABC is a triangle. The angles in a triangle must add up to 180 degrees. Therefore:
We know two angles: ∠B= 48° and ∠A= 90° (the little square denotes a right angle).
- 90°+48°+ ∠C= 180° <em>Substitute values in.</em>
- 138°+ ∠C =180° <em>Add</em>
- 138°-138° ∠C= 180°-138° <em>Subtract 138 from both sides.</em>
- ∠C= 42°
Note that angle C is part of another triangle. It is isosceles because the two legs (CD and CE) are congruent. Therefore, the two base angles (E and D) are congruent.
- ∠C+∠D+∠E= 180°
- ∠C+ 2∠D= 180° <em>Angles D and E are congruent</em>
- 42°+ 2∠D= 180° <em>Substitute 42 in for angle C</em>
- 42°-42° +2∠D= 180°-42° <em>Subtract 42 from both sides.</em>
- 2∠D= 138°
- 2∠D/2= 138°/2 <em>Divide both sides by 2.</em>
- ∠D= 69°
∠D and ∠E equal 69 degrees.
Angle CED (∠E) and DEB are on a straight line together. Therefore, they are supplementary and equal 180 degrees.
- ∠CED+ ∠DEB= 180
- 69° +∠DEB= 180° <em>Substitute 69 for angle CED</em>
- 69°-69° +∠DEB= 180°-69° <em>Subtract 69 from both sides</em>
- ∠DEB=111°
Angle DEB is equal to <u>111 degrees</u>
