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Pavlova-9 [17]
2 years ago
11

Your newest coworker is not as productive as other members of your team. You and your coworkers have to work harder to make up f

or this.
What would you be most and least likely to do?

(A).Be patient. Give her more time to learn the job so that her productivity will increase.

(B).Ask her how the job is going. Let her know you're available if she has any questions.

(C).Give her advice and tips for how to get things done correctly and efficiently.

(D).Talk to your supervisor about the situation. Suggest that this might not be the best role for your coworker.
Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
3 0

Answer:

(C) Give her advice and tips for how to get things done correctly and efficiently.

Explanation:

You would be most and least likely to: Provide her with suggestions and pointers on how to complete tasks correctly and efficiently.

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D.) \frac{3}{4}

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Find the area of the shaded region
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∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm

where h is the length of the altitude originating from vertex O, and so

\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm

where b is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

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