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8_murik_8 [283]
4 years ago
9

there are 60 boys and 72 girls in a school. the principle wants to divide the students into gender-specific groups ( all boys or

all girls) of the largest possible size. Each group needs to have the same number or students. What is the correct size of each group?

Mathematics
1 answer:
Tamiku [17]4 years ago
7 0
Hello there,
You want to split them into gender specific groups.
So...
Find the HCF(highest common factor) of 60 & 72 
The answer will be shown in the picture
I have done 2 methods :))


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Make x the subject of m=n+x/p
viva [34]

I COULDN'T KNOW WHERE THE DOVISUON SIGN WAS ACTUALLY SO THERE ARE TWO ANSWER CHOOSE ANY ONE

4 0
3 years ago
don't worry about the other writing I want to see it worked out step by step so I can work the rest out and learn how to do them
artcher [175]

Answer:

see below

Step-by-step explanation:

6y = 12x + 26

15y = 45x + 60

First let's simplify these equations.

6y = 12x + 26

Divide each term by 6.

y = 2x + 26/6

Simplify the fraction.

26/6

= 13/3

Your simplified equation is:

y = 2x + 13/3

Let's simplify the other equation.

15y = 45x + 60

Divide each term by 15.

y = 3x + 4

These are your simplified equations.

y = 2x + 13/3

y = 3x + 4

We can see that the slope of the first equation is not equal to the slope of the second equation.

  • equation 1: slope is 2 shown from 2x
  • equation 2: slope is 3 shown from 3x

The y-intercept of the first equation is not equal to the y-intercept of the second equation.

  • equation 1: y-intercept is 13/3 shown by + 13/3
  • equation 2: y -intercept is 4 shown by + 4

Now we want to solve the equations.

Both equations are equal to y, so you can set them equal to each other.

2x + 13/3 = 3x + 4

Combine like terms.

1/3 = x

Plug x = 1/3 into both of the equations separately..

y = 2(1/3) + 13/3

y = 2/3 + 13/3

y = 15/3

y = 5

y = 3(1/3) + 4

y = 3/3 + 4

y = 1 + 4

y = 5

Your solution is (1/3, 5)

The system of equations has one solution.

Hope this helps!

4 0
3 years ago
Confused about this...
Brut [27]

Answer:

See attachment

Step-by-step explanation:

C and D are parallel planes and the FG line should be intersecting it at two points : F and H

(Caution: since the places of intersection (as stated in the problem) is F and H, I assumed that in intersection point of the plane C is where the FG line starts)

Goodluck on your homework and have a nice day)

5 0
3 years ago
Help?? Me pleaseeee, you must help
storchak [24]
C is your answer e cause u supposed to multiple
7 0
4 years ago
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What's the area of the triangle below
grigory [225]
To find the area<span> of a </span>triangle<span>, multiply the base by the height, and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into 2 triangles. For example, in the diagram to the left, the </span>area<span> of each </span>triangle<span> is equal to one-half the </span>area<span> of the parallelogram. their is your answer </span>
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4 years ago
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