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8_murik_8 [283]
3 years ago
9

there are 60 boys and 72 girls in a school. the principle wants to divide the students into gender-specific groups ( all boys or

all girls) of the largest possible size. Each group needs to have the same number or students. What is the correct size of each group?

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0
Hello there,
You want to split them into gender specific groups.
So...
Find the HCF(highest common factor) of 60 & 72 
The answer will be shown in the picture
I have done 2 methods :))


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x=8

Step-by-step explanation:

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Friday, a store sold 10 blue shirts and 20 white shirts. what percentage of the shirts sold were blue? give answer to the ones p
jasenka [17]

Answer:

10+20=30

10 is what percent of 30?

10 is 1/3 of 30

Step-by-step explanation:

10 is 33.33% of 30

so 33% of the shirts sold were blue

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How many different ways can you write a fraction that has a numerator of 2 as a sum of fractions
Rzqust [24]
At least you can write it as the sum of half of it twice, that is:
2/x = 1/x + 1/x
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7 0
3 years ago
HI can you help me with this problem?The quantity demanded x for a certain brand of MP3 players is 300 units when the unit price
Vlad [161]

The demand equation is P = -0.05x + 105

STEP - BY - STEP EXPLANATION

What to find?

<em>The demand equation.</em>

The following information is used to solve the problem.

If (x₁ , y₁) and (x₂, y₂) are any dinstinct points on a line a non-vertical line L, then the equation of the line that has a slope(m) and passes through the point (x₁ , y₁) is given by the formula below:

y-y_1=_{}\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Assume p, be the unit price and x be the demand when the price is $p.

From the question given, when the unit price x = 300 units, the demand p = $90 and when the unit price x = 1300 units, the demand p = $40

This means the demand curve passes through the points (300, 90) and (1300, 40).

Assume the demand equation is linear, then the line of the equation passes through the points (300, 90) and (1300, 40).

Now;

y=p x₁ =300 y₁ = 90 x₂ = 1300 y₂=40

Substitute the values into the function and simplify.

p-90=\frac{40-90}{1300-300}(x-300)

Simplify the above.

p-90=\frac{-50}{1000}(x-300)p-90=-0.05(x-300)

Open the parenthesis.

P- 90 = -0.05x + 15

Add 90 to both-side of the equation.

P = -0.05x + 15 + 90

P = -0.05x + 105

Hence, the demand function is P = -0.05x + 105

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If b=3 what does -3b equal
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