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FromTheMoon [43]
3 years ago
7

Round 12.034 to the nearest tenth

Mathematics
2 answers:
Sonja [21]3 years ago
8 0
Answer is 12 good luck!
slega [8]3 years ago
7 0
The answer is 12.  Thanks (;
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A 10-ounce box of cereal cost $3. A 20-ounce box of the same cereal cost $5. A third box of the same cereal costs $8.
kvasek [131]

The number of ounces of cereal in the third box is 32.

<u>Explanation:</u>

Given-

10 oy box = $3

Price of 1 ounce box = $3/10

                                  = $0.3

20 oy box = $5

Price of 1 oy box = $5/20

                            = $0.25

Therefore, it is beneficial to buy a 20 oy box as it is comparatively cheaper than the 10 oy box.

Third box of cereal = $8

$5 is the price of 20 oy box

$8 will be the price of x oy box

So,

x = \frac{20}{5} X 8\\ \\x = 32

Therefore, the number of ounces of cereal in the third box is 32.

3 0
3 years ago
Find the missin value in the ratio table
Snowcat [4.5K]

20

U have to divide it by 3 the ratio is 1:3

4 0
2 years ago
I really need help guys can some one plz help me it's for 10 points
11111nata11111 [884]

Answer:

\sqrt{8}----- 2units,2units

\sqrt{7} ------\sqrt{5}units,\sqrt{2}units

\sqrt{5}-------1unit,2units

3------2units, \sqrt{5}units

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

1. a=\sqrt{5}, b=\sqrt{2}

Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

c=\sqrt{5+2}\\ c=\sqrt{7}

2. a=\sqrt{3}, b=4

c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}

3. a=2, b=\sqrt{5}

c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3

4. a=2, b=2

c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}

5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

7 0
3 years ago
X^2 + 5x = quadratic equation <br>=​
timama [110]

Hi there!

The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation. 

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}  

x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}  

x = \frac{-5 \pm \sqrt{25 - 12} }{2}  

x = \frac{-5 \pm \sqrt{13} }{2}  

x = \frac{-5 \pm 3.61 }{2}  

x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}

x=-0.695 \ \textgreater \ \ \textgreater \  -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31

Therefore, the solutions to the quadratic equation  are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!

Your answer is 4.31

4 0
3 years ago
Can a function be linear if it is exponential?
Shtirlitz [24]

Answer:

yep

Step-by-step explanation:

for example y=x^2 is a linear exponential

3 0
3 years ago
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