A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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20% 25-20 equals 5. 5 divided by 20 equals .2 or 20%
Answer:
c.18
Step-by-step explanation:
32/24=1.33333333333
40/30=1.33333333333
24/1.33333333333=18
Please find the attachment.
Let x represent the side length of the squares.
We have been given that an open box is made from an 8 by ten-inch rectangular piece of cardboard by cutting squares from each corner and folding up the sides. We are asked to find the volume of the box.
The side of box will be
and
.
The height of the box will be
.
The volume of box will be area of base times height.
![\text{Volume of box}=(8-2x)(10-2x)\cdot x](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D%288-2x%29%2810-2x%29%5Ccdot%20x)
Now we will use FOIL to simplify our expression.
![\text{Volume of box}=(80-16x-20x+4x^2)\cdot x](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D%2880-16x-20x%2B4x%5E2%29%5Ccdot%20x)
![\text{Volume of box}=(80-36x+4x^2)\cdot x](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D%2880-36x%2B4x%5E2%29%5Ccdot%20x)
Now we will distribute x.
![\text{Volume of box}=80x-36x^2+4x^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20box%7D%3D80x-36x%5E2%2B4x%5E3)
![V(x)=80x-36x^2+4x^3](https://tex.z-dn.net/?f=V%28x%29%3D80x-36x%5E2%2B4x%5E3)
Therefore, the volume of the box would be
.