Answer:
B-14
Step-by-step explanation:
Divide 220.50 by 15.75 and you will get 14
Hope it can help you lovelots
Answer:
The rate of change is
ft^(2)/min
Step-by-step explanation:
The area of a circle is given by the following equation:

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

We have that:
.
We want to find 
So


Since the area is in square feet, the rate of change is in ft^(2)/min.
So the rate of change is
ft^(2)/min
Answer:
They would need approximately 20 gallons of paint for the water tower, so yes, 25 gallons would be enough.
Step-by-step explanation:
In order to find out if there is enough paint for the surface area of the sphere, you need to first find the radius of the object so you can determine the measure of the entire surface area. Since they give us the volume, we can use that to solve for the radius using the volume formula: V = πr³ or 66840.28 = πr³. Using inverse operations, you can first multiply both sides of the equation by the reciprocal of 4/3 or 3/4, then divide by π, this gives you 15,965 = r³. In order to find 'r', take the cube root of both sides: ∛15965 = ∛r³ or r ≈ 25.
Now that you know radius = 25, you can use the formula for surface area: SA = 4πr² or 4π(25)² ≈ 7850 ft². Since one gallon of paint covers 400 square feet, we can take our total and divide by 400 to find the number of gallons: 7850 ÷ 400 ≈ 19.6. In total, we would need 19.6 gallons of paint for the water tower, so if there are 25 gallons available, there is enough.
Answer:
x ≤ $12 a day
Step-by-step explanation:
5000-1400=3600
3600/300=12
Henry needs to sale 14 rings for his revenue to equal his expenses.
Step-by-step explanation:
Given,
Selling price of ring = $8
Expense on one ring = $1.50
Cost of supplies = $91
Let,
x represent the number of rings.
Expenses = 91+1.50x
Revenue = 8x
Equal expenses means;
Revenue = Expenses

Dividing both sides by 6.5

Henry needs to sale 14 rings for his revenue to equal his expenses.
Keywords: revenue, division
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