<span> 63 in four different ways
1) 63 ones
2) 6 tens and 3 ones
3) 3 tens and 33 ones
4) 4 tens and 23 ones</span>
This question was answered but no solution was given.
We already solve for the B or area of the triangular base which was 5.25cm².
There are 2 triangular faces in the prism so 5.25cm² x 2 = 10.50cm²
There are 3 rectangular face in the prism, we need to get the area of each.
area of a rectangle = length x width
rectangle 1: 5 cm x 4 cm = 20 cm²
same dimension with rectangle 2. so, area is 20 cm² also
rectangle 3: 5 cm x 2.8 cm = 14 cm²
let us all add up the area of each surface.
2 triangle = 10.50 cm²
3 rectangles = 20 cm² + 20 cm² + 14 cm² = 54 cm²
10.50 cm² + 54 cm² = 64.50 cm²
Is this a question on your test or something? I know trying out every number and letter would be difficult. There is a way to solve these types of problems. Ask your math teacher, or someone that knows this or has taught this.
I think it is acute because below 90 is acute above 90 is obtuse and exactly 90 is right
<span> -5a^2-19a^2-5a-8+12a^2-22-14a-2a
first gather all same powers
-5a</span>²-19a²+12a²-5a-14a-2a-8-22
-12a²-21a-30
-3(6a²+7a-+10)
