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user100 [1]
3 years ago
14

A zookeeper predicted the weight of a new baby elephant to be 265 pounds when it was born. The elephant actually weighed 297 pou

nds at birth. What was the percent error of the zookeeper's prediction?
Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer: 10.7741077410774...

Step-by-step explanation: The formula for percent of error is (absolute value of prediction-actual)/actual times 100 so it is |265-297|/297 times 100 which is

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Step-by-step explanation:

The smallest value in the sample data is min = 50 dollars and the largest value is max = 2500 dollars, therefore, the range is Range = max - min = 2500 - 40 = 2460 dollars. On the other hand, the formula to compute the sample variance is S^2 = \frac{1}{n-1}\sum_{i=1}^{n} (x_{i}-\bar{x})^2 where \bar{x} is the sample mean, n is the sample size and the x_{i} are the sample values. In this case the sample variance is s^2 = 516414.6 dollars^2, the sample standard deviation is defined as the squared root of the sample variance, so, the sample standard deviation is s = 718.6199 dollars. There are two outliers because 1750 dollars and 2500 dollars are very different compared to the other values, these two numbers are very large and they are likely to have much of an effect on the measures of variation because these measures are sensible to outliers, they are no robust measures.

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