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Alenkasestr [34]
2 years ago
6

11^-x-4 = 7^8x Thank you

Mathematics
1 answer:
Nonamiya [84]2 years ago
4 0

Answer:

x = \frac{4ln(11)}{-ln(11)-8ln(7)}

Step-by-step explanation:

(-x-4)ln(11) = 8xln(7)

(-x-4)/(8x) = ln(7)/ln(11)

x = \frac{4ln(11)}{-ln(11)-8ln(7)}

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Which fact is related to 12 = 3 = 4?<br> I need help
Svetach [21]

Answer:

factors

Step-by-step explanation:

3 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
The length of a rectangle is twice its width. if the area of the rectangle is 128 ft2 , find its perimeter.
kupik [55]
Length(l)= 2w
Width(w)= w
Area(A) = l*w

A= 128 ft²
128= l*w
128= (2w)w
2w²= 128
w²= 64
w=√64= 8 ft
w= 8 ft

length(l)= 2w
l=2(8)
l=16 ft

P= 2l+2w
P=2(16)+2(8)= 32+16= 48ft
P= 48ft

Answer:
The Perimeter of this rectangle is 48 feet.


Leave any questions you still have in the comments below please! Thank you! Hope this helped! :)
5 0
3 years ago
0.8 times x is less than 0.6
suter [353]

False. Anything times 0.8 except 0, is 0.8 or more.

8 0
3 years ago
Find the GCF of 30, 60, and 78.
Sloan [31]
The greatest common factor is six.
6 0
3 years ago
Read 2 more answers
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