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Alenkasestr [34]
2 years ago
6

11^-x-4 = 7^8x Thank you

Mathematics
1 answer:
Nonamiya [84]2 years ago
4 0

Answer:

x = \frac{4ln(11)}{-ln(11)-8ln(7)}

Step-by-step explanation:

(-x-4)ln(11) = 8xln(7)

(-x-4)/(8x) = ln(7)/ln(11)

x = \frac{4ln(11)}{-ln(11)-8ln(7)}

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What is the total amount, including interest, that the shoe store must pay on the loan? (2 points)
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Answer:

2550

Step-by-step explanation:

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What is the standard form of this polynomial: 7 - x³ + 2x - 4x²?
Nadya [2.5K]

Answer:

−x^3−4x^2+2x+7

Step-by-step explanation:

3 0
2 years ago
Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom
IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed  of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0
3 years ago
What is the coefficient in the expression shown?
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Answer:

In mathematics, a coefficient is a multiplicative factor in some term of a polynomial, a series, or any expression; it is usually a number, but may be any expression.  

Step-by-step explanation:

3 0
2 years ago
Chloe is painting on a stretched canvas that has an area of 108 square inches. The length of the canvas is 12 inches. The width
Stolb23 [73]

Answer: Width of canvas = 9 inches

Area left for painting after painting the border = 70 square inches.

Explanation :

Since we have given that

Area of painting = 108 square inches

Length of canvas = 12 inches

As we know that

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108=12\times breadth\\\\\frac{108}{12}=breadth\\\\9=breadth

So, breadth of canvas = 9 inches .

Now, Chloe paints a 1 inch wide blue border on the canvas.

\text{So, remaining length left for painting after painting the border} = 9-1-1=9-2=7\text{ inches}

\text{ Remaining breadth left for painting after painting the border }= 12-1-1=12-2= 10\text{ inches}

\text{So , area of remaining portion }= length\times breadth \\\\ \text{ area of remaining portion }=7\times 10\\\\\text{ area of remaining portion }=70 \text{ square inches}

Hence, remaining area = 70 square inches .

6 0
2 years ago
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