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KiRa [710]
3 years ago
7

Help with question 17!

Mathematics
1 answer:
solniwko [45]3 years ago
8 0
Do you have to find the angle or the measurement?
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Pls help pls pls ): precalc
Lena [83]
<h3>Answer: Choice A</h3>

\log_p N = b is not the same as b^p = N

The base of the log is p, while the base of the exponential is b. The two don't match. If it said \log_p N = b \text{ is the same as } p^b = N then it would be a valid statement since the bases are both p.

-----------------

Extra info:

Choice B is a valid statement because Ln is a natural log with base 'e'

Choice C is valid as any square root is really something to the 1/2 power

Choice D is valid for similar reasons mentioned earlier

5 0
3 years ago
Read 2 more answers
PLLLZZZZZ HEEEEELLLLPPPPPPP
IceJOKER [234]
The answer should be C. 
4 0
3 years ago
Read 2 more answers
B) State whether the given pairs are complementary, supplementary or neither.
yawa3891 [41]

Answer:

1st answer supplementary angles

2nd answer complementary angles

3rd answer neither

4th ananswe complementary angles

5th answer complementary angles

6th answer supplementary angles

hope you find this helpful

3 0
2 years ago
PLEASE HELP ME ITS AREA OF COMPOUND SHAPES ILL MARK U A BRAINIST PERSON IF YOUR RIGHT PLEASE HELP
ddd [48]

Answer:

32 in^2.

Step-by-step explanation:

Area = area of the triangle + area of rectangle

        = 1/2 * 4 * 6 + 4 * 5

        =  12 + 20.

7 0
3 years ago
Help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
worty [1.4K]

Step-by-step explanation:

{x}^{2}  = 2  \times {4}^{2}  \\  {x}^{2} = 32 \\ x  =  4 \sqrt{2}   \\ diameter = 4 \sqrt{2}  \\ radius = 2 \sqrt{2}  \\ area \: of \: half \: of \: the \: circle =  \\

a =  \frac{\pi \times {(2 \sqrt{2} )}^{2}  }{2}  = 4\pi \\ area \: of \: triangle \:  =  \\ 2 \sqrt{2}  \times 2 \sqrt{2}  = 8 \\ area \: of \: shaded \: region \: is \:  =  \\ 4\pi - 8 = 4.57 \:  {cm}^{2}

6 0
3 years ago
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