1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paladinen [302]
3 years ago
5

The original price of a bicycle was $100.00. In March, a bicycle went on sale for 10% off. In April, the sale price was raised b

y 10%. What is the price of the bicycle in April? Write just the value that represents your answer.
Mathematics
1 answer:
trapecia [35]3 years ago
5 0

Answer:

take 10% out of 100 = 90

then find 10% of 90 = 9

add that to 90 = 99

The price of the bike in april is 99$

psl mark me as brailyest:)

You might be interested in
Express 3.01 as a mixed number
Len [333]
The three would be the whole number while 01 would be the fraction. And since the 1 is 2 places from the decimal it would mean that it is going to be out of 100. Therefore the answer is 3 1/100
8 0
3 years ago
Match the parabolas represented by the equations with their foci.
Elenna [48]

Function 1 f(x)=- x^{2} +4x+8


First step: Finding when f(x) is minimum/maximum
The function has a negative value x^{2} hence the f(x) has a maximum value which happens when x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2. The foci of this parabola lies on x=2.

Second step: Find the value of y-coordinate by substituting x=2 into f(x) which give y=- (2)^{2} +4(2)+8=12

Third step: Find the distance of the foci from the y-coordinate
y=- x^{2} +4x+8 - Multiply all term by -1 to get a positive x^{2}
-y= x^{2} -4x-8 - then manipulate the constant of y to get a multiply of 4
4(- \frac{1}{4})y= x^{2} -4x-8
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is 12- \frac{1}{4}=11.75

Hence the coordinate of the foci is (2, 11.75)

Function 2: f(x)= 2x^{2}+16x+18

The function has a positive x^{2} so it has a minimum

First step - x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4
Second step - y=2(-4)^{2}+16(-4)+18=-14
Third step - Manipulating f(x) to leave x^{2} with constant of 1
y=2 x^{2} +16x+18 - Divide all terms by 2
\frac{1}{2}y= x^{2} +8x+9 - Manipulate the constant of y to get a multiply of 4
4( \frac{1}{8}y= x^{2} +8x+9

So the distance of focus from y-coordinate is \frac{1}{8} to the north of y=-14
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: f(x)=-2 x^{2} +5x+14

First step: the function's maximum value happens when x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25
Second step: y=-2(1.25)^{2}+5(1.25)+14=17.125
Third step: Manipulating f(x)
y=-2 x^{2} +5x+14 - Divide all terms by -2
-2y= x^{2} -2.5x-7 - Manipulate coefficient of y to get a multiply of 4
4(- \frac{1}{8})y= x^{2} -2.5x-7
So the distance of the foci from the y-coordinate is -\frac{1}{8} south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when x=8.5 and y=79.25. The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when x=-2.75 and y=-10.125. Manipulating coefficient of y, the distance of foci from y-coordinate is \frac{1}{8} to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when x=1.5 and y=9.5. The distance of the foci from the y-coordinate is \frac{1}{8} to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

8 0
3 years ago
The area of a square is 20 square which best represent the length of the side of the square
mote1985 [20]
5' per side or whatever units it's measured in, because 4x5=20
8 0
3 years ago
Find S^20 if the series 1 + 1.1 ..... is a (a) arithmetic (b) geometric
quester [9]
I'm guessing S^20 is actually referring to the 20th partial sum S_{20}, with

S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)

in the arithmetic case, and

S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}

in the geometric case.

(a) Combining like terms, we have

S_{20}=20+0.1(1+2+\cdots+18+19)

and invoking the formula

1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2

we end up with

S_{20}=20+0.1\dfrac{19\times20}2=39

(b) Multiply S_{20} by 1.1, then subtract this from S_{20}:

1.1S_{20}=1.1+1.1^2+1.1^3+\cdots+1.1^{19}+1.1^{20}

S_{20}-1.1S_{20}=-0.1S_{20}=1-1.1^{20}
\implies S_{20}=\dfrac{1.1^{20}-1}{0.1}\approx57.275
7 0
3 years ago
Tiva earns $48 for 6 hours of babysitting. Complete each statement if Tiva keeps earning her babysitting money at this rate. CLE
lawyer [7]
8.5
= (48 \div 6) \times 8.5
8 \times 8.5
= 68

$32

Perhour =8
32/8 =4 hours
3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the degree of x^3+2x-3x^4+5+3x^2
    15·1 answer
  • What the measure of a interior angle of a six sided figure
    14·1 answer
  • What is the measure of angle b
    11·1 answer
  • Between which Two numbers will you find 5.634 x 10
    9·1 answer
  • Which expression has a value of 24?
    10·2 answers
  • What is the solution of the system of equations?<br><br> y = x - 10<br><br> y = 2x + 5
    12·1 answer
  • Which lines are perpendicular to the line y - 1 = 1(x+2)? Check all that apply.
    11·1 answer
  • I think it’s A not sure
    14·1 answer
  • Please help I need it ASAP!!!!
    12·1 answer
  • Question 18 (5 points)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!