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White raven [17]
3 years ago
7

Convert 7.0055 into a mixed number in simplest form

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
7 0
7.0055=7\frac{55}{10000}=7\frac{11}{2000}
Scorpion4ik [409]3 years ago
4 0
7.0055=<u>70055</u>  =<u /> <u />7  <u>55</u>      =7   <u>11</u>
            10000        10000       2000
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her battery will lost for 3.6 hours

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3 years ago
A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random
melomori [17]

Answer:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

p_v =P(t_{(13)}  

If we compare the p value and the significance level given \alpha=0.05 and we can see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=24 represent the sample mean

s=2.2 represent the sample standard deviation

n=14 sample size  

\mu_o =25 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for the average speed is lower than 25 mph, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=14-1=13  

Since is a one side test the p value would be:  

p_v =P(t_{(13)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 and we can see that p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can't conclude that the true average speed is lower than 25 mph at 5% of signficance.  

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3 years ago
Write each sum as a product of the GCF of the two numbers 36 and 45
nika2105 [10]
The GCF of both numbers is 9. So 9 goes outside the parentheses. The numbers multiplied by the GCF to get 36 and 45 are 3 and 5. The answer is 9 ( 3 + 5 )
4 0
3 years ago
Which of the following place value tables shows 40,833?
jolli1 [7]

40,833 has...

4 Ten Thousands

8 Hundreds

3 Tens

3 Ones

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4 years ago
Need help fast please
dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is  -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4


14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0


15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x


16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

y=3x-10


 

8 0
4 years ago
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