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3 years ago

Witch is greater 16.45 or 16.454

Mathematics

2 answers:

Leokris [45]3 years ago

6 0

16.45 is equal to 16.450, so 16.454 is grater.

Hope this helps!

Alex73 [517]3 years ago

5 0

16.454 because it has and extra .004 than 16.45

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PLEASE HELP!

Cloud [144]

The short answer is trial and error. The side lengths "3" and "4" can both be substituted for a² and b² but not c² because their value squared is not high enough since 5² is 25. "c²" as to match the longest side because the smaller numbers will cause the equation to not be true. See Below.

a² + b² = c²
3² + 4² = 5²
9 + 16 = 25
25 = 25
______________________________

a² + b² = c²
4² + 3² = 5²
16 + 9 = 25
25 = 25
______________________________

a² + b² = c²
5² + 4² = 3²
25 + 16 = 9
41 ≠ 9

______________________________

a² + b² = c²
3² + 5² = 4²
9 + 25 = 16
34 ≠ 16

Hope this helped!

7 0

3 years ago

a woman has $28,000. part is invested for one year in a certificate of deposit paying 7% interest, and the remaining amount in c

alexira [117]

Answer:

Amount invested at 7% = 16000

Amount invested at 9% = 12000

Step-by-step explanation:

Let x be the amount invested at 7% and y be the amount invested at 9%.

Since the total amount invested is $28000, therefore, we can set up the first equation as:

$x+y=28000$

Secondly, we are give that sum of two investments is $2200. Therefore, we can write the second equation as:

$0.07x+0.09y=2200$

Now we need to solve these two equations to get the values of x and y.

First of all, we multiply the second equation with 100 in order to get rid of decimal values.

$(0.07x+0.09y)*100=2200*100\\7x+9y=220000$

Let us use substitution method here. First of all we will solve for y from first equation and plug that into second equation.

$y=28000-x$

$7x+9(28000-x)=220000\\7x+252000-9x=220000\\-2x=-32000\\x=16000$

Therefore, amount invested at 7% is $16000 and amount invested at 9% is 28000-16000=$12000.

7 0

3 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$

5 0

4 years ago

Please help me with +=−

marishachu [46]

Step-by-step explanation:

hello ...........sksnsbszbsjs

4 0

3 years ago

Paul predicts that n stalks of corn planted together will produce (2n2–2n)(2n2–2n) ears of corn. If Paul plants three corn plant

Free_Kalibri [48]

Given that the production of n stalks of corn planted has been modeled by (2n^2-2n), then the approximate ears of corn produced by 3 stalks will be given by:
2n^2-2n
plugging in n=3 in the formula we get:
2(3)^2-2(3)
simplifying we get:
2(9)-6
=18-6
=12
the answer is: 12 ears

6 0

4 years ago