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Serjik [45]
3 years ago
13

Colin rolls a fair dice 18 time, how many times would colin expect to roll an odd number?

Mathematics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

9

Step-by-step explanation:

a normal dice is 6 sides

half of 18 is 9

50% for odd and even

m_a_m_a [10]3 years ago
4 0

Answer:

9 times

Step-by-step explanation:

Because you have an equal chance of rolling an odd or even number on the die. So half of 18 is 9.

Have a great day, would love it if you would mark me brainliest!

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How would you do this question?
diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0
3 years ago
Apply the distributive property to create an equivalent expression. 5 × ( − 2 w − 4 )
madreJ [45]

Answer:

5(-2w)-(5x4)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is a 96% confidence interval for the proportion of weight-lifting injuries in this age group that were accidental?
loris [4]
<span>A 96% confidence interval means that 96% of the time you can believe that the result will fall into a range of numbers. In the case of weight lifting this would mean that 96% of the time, the proportion of weight-lifting injuries were accidental would fall in between the two parameters set forth.</span>
8 0
3 years ago
What whole number dimensions would allow the students to maximize the volume while keeping the surface area at most 160 square f
ycow [4]

Answer:

The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft

Step-by-step explanation:

Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²

For maximum volume, the side length, s of the cube must all be equal ;

Therefore area of one side = s²

Number of sides in a cube with top open = 5 sides

Area of surface = 5 × s² = 180

Therefore s² = 180/5 = 36

s² = 36

s = √36 = 6 ft

Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.

6 0
3 years ago
Need Help ASAP!
poizon [28]
No the solution should only be X=1
5 0
3 years ago
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