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Marizza181 [45]
3 years ago
6

Which calculator correctly shows the quotient of6.47 x 10-153.36 * 10-29 ​

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Answer: The one that ends in +14

Step-by-step explanation:

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PLEASE ANSWER CORRECTLY, I WILL GIVE BRAINLIEST <3 THANKS IN ADVANCE!
guajiro [1.7K]

Answer:

1 : 15

2: 12

3: 52

4: 27.3

Step-by-step explanation:

For #1:

if line m and n are perpendicular then they will create right angles

Right angles have a measure of 90 degrees

That being said we can find the measure of the missing angle by subtracting the measure of the known angle (75) from 90

so k = 90 - 75

90 - 75 = 15

Hence k = 15.

For #3 ( very similar to #1, only difference is the values of the angles )

so R = 90 - 38

90 - 38 = 52

Hence, R = 52

For #2 and #4

Complementary angles have a sum of 90°

So like the previous questions we can find the measure of the missing angle by subtract the measure of the given angle from 90

∠V = 90 - 78

90 - 78 = 12

Hence ∠V = 12

∠Y = 90 - 62.7

90 - 62.7 = 27.3

Hence ∠Y = 27.3

6 0
2 years ago
I NEED HELP WITH A PROBLEM​
Lapatulllka [165]

Answer:

39

Step-by-step explanation:

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3 years ago
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Solve by factoring: x^4-12x^2= 64
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Step-by-step explanation:

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3 years ago
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George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at t
arsen [322]

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

6 0
3 years ago
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