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2 years ago

8

Use the graph of the parabola to fill in the table

1 answer:

Furkat [3]2 years ago

5 0

(a) The parabola opens downward.

(b) The axis of symmetry is at x = -2.

(c) The vertex is at (-2,0).

(d) The x-intercepts is (-2,0), and the y-intercept is at (0,-1).

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PlS help lots of points

Len [333]

I feel like there is something missing from this question, for example how large is the tree house? If these are just plain measurements, then I would opt for B.

3 0

2 years ago

An observer stands 25 feet from the base of a flagpole and watches a flag being lowered at a rate of 5 ft/sec. Determine the rat

Sedaia [141]

Answer:

0.1 rad/s

Step-by-step explanation:

Since the distance from or to the flagpole is not given, I will assume. And my assumption is 50 ft

Now, the elevation angle A = 45 degrees, converting to radians, we have π/4 radians

Remember that the tan of an angle is OPP/HYP, and so

tan A = h/25, on differentiating, we have

d tan A/dA = sec^2 A = (1/25) dh/dA

Next, we have

25 sec^2 A * dA/dt= dh/dt = 5

Making dA/dt the subject of formula, we have

dA/dt = (1/5) cos^2 A

but cos^2 A from trigonometry = 1/2, this means that

dA/dt = .1 radians/second

If you want to convert to degrees, your have

.1 Rad/s( 180 deg/rad) = 18 degrees/second

3 0

3 years ago

Study the equation.<br> y = x2 - 4x - 77<br> Write the equation in graphing form (vertex form).

Julli [10]

Answer:

y=(x-2)^2-81

Step-by-step explanation:

4 0

3 years ago

Anacondas are snakes found in South America anacondas can measure over 16 1/2 feet in length how many inches are in 16 1/2

OLga [1]

Answer:

198 inches

Step-by-step explanation:

There are 12 inches in each foot

multiply 16 by 12 you get 192

Half of a foot is 6 inches

add 6 inches and you get 198

5 0

3 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago