Parameterize S by the vector function

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.
Compute the outward-pointing normal vector to S :

The integral of the field over S is then



The number would be 12. If you substitute you will find that 12 is correct.
1 and 2 both have 1/4th slope, (2 is y=.25x +2.8)
3 has 1/4th slope, (y = 1/4x - 8/5)
4 has a -1/4th slope.
H would be correct as all the others have a 1/4th slope and IV is only one with a -1/4th slope
Answer:
y = 5/2x
y = 35/2
Step-by-step explanation:
direct variation
y = kx
Substitute the values for x and y
15 = k(6)
Divide each side by 6 yo find k
15/6 = k
5/2 = k
The equation is y = 5/2 x
Now we know x =7
y = 5/2(7)
y = 35/2
Answer:
I think missing values is -4