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3 years ago

The quote for GBP/USD is listed as 1.5869/76 as shown. How many U.S. dollars does it cost to buy 1 British pound?

Mathematics

2 answers:

Finger [1]3 years ago

7 0

Exact Rate Right Now 1.35185 USD

harkovskaia [24]3 years ago

4 0

Answer:

1.586976 US Dollars

Step-by-step explanation:

Great Britain Pound/United States Dollar = 1.586976

$\frac{\text{1 Great Britain Pound}}{\text{1 United States Dollar}}=1.586976\\\Rightarrow \text{1 Great Britain Pound}=1\times 1.586976 \text{1 United States Dollar}}$

This means that 1.586976 United States Dollar is need to buy 1 British pound.

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nevsk [136]

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3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

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$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

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2 years ago

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Katen [24]

Answer:

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Step-by-step explanation:

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Answer:

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2 years ago

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